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# Is xy<O? 1) 1/x<1/y 2) x>0

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Manager
Joined: 24 Jun 2003
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Is xy<O? 1) 1/x<1/y 2) x>0 [#permalink]

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08 Aug 2003, 11:57
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Is xy<O?

1) 1/x<1/y
2) x>0

Kudos [?]: 4 [0], given: 0

Manager
Joined: 25 Apr 2003
Posts: 227

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08 Aug 2003, 23:42
seconded. condition 1 tells us x>y, condition 2 tells us x>0. For getting xy<0 , we need to have y<0 even after cobining two statements. therefore E.

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Manager
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Location: India
Re: DS practice # 10 [#permalink]

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09 Aug 2003, 05:49
Konstantin Lynov wrote:
Is xy<O?

1) 1/x<1/y
2) x>0

Agree with E

(1) gives x>y
(2) gives x>0

Combining, still cannot answer the question

Kudos [?]: 3 [0], given: 0

Manager
Joined: 24 Jun 2003
Posts: 91

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Location: Moscow
Re: DS practice # 10 [#permalink]

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12 Aug 2003, 00:04
Konstantin Lynov wrote:
Konstantin Lynov wrote:
Is xy<O?

1) 1/x<1/y
2) x>0

E is wrong!

Statement 1 - not sufficient. X and Y could both be either positive or negative. X could be positive and Y could be negative and the other way around.

Statement 2 - not sufficient. No comments on this one.

Combine: sufficient. Think about it, if we know that x>0(2), y must be>0(1). Thus, it is sufficient to state that xy is not < 0.
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Respect,

KL

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Location: New York NY 10024
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Re: DS practice # 10 [#permalink]

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12 Aug 2003, 00:11
prashant wrote:
Konstantin Lynov wrote:
Is xy<O?

1) 1/x<1/y
2) x>0

Agree with E

(1) gives x>y
(2) gives x>0

Combining, still cannot answer the question

(1) is a valid conclusion ONLY IF x and y are both positive or both negative.
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Best,

AkamaiBrah
Former Senior Instructor, Manhattan GMAT and VeritasPrep
Vice President, Midtown NYC Investment Bank, Structured Finance IT
MFE, Haas School of Business, UC Berkeley, Class of 2005
MBA, Anderson School of Management, UCLA, Class of 1993

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Re: DS practice # 10   [#permalink] 12 Aug 2003, 00:11
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