It is currently 12 Dec 2017, 07:20

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Is |xy| + xy <= 0? 1/ |x| + xy <= 0 2/ |y| + xy <=

Author Message
Intern
Joined: 29 Sep 2009
Posts: 16

Kudos [?]: 36 [0], given: 3

Is |xy| + xy <= 0? 1/ |x| + xy <= 0 2/ |y| + xy <= [#permalink]

### Show Tags

02 Oct 2009, 02:04
00:00

Difficulty:

(N/A)

Question Stats:

100% (00:19) correct 0% (00:00) wrong based on 1 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Is |xy| + xy <= 0?

1/ |x| + xy <= 0
2/ |y| + xy <= 0

Kudos [?]: 36 [0], given: 3

Director
Joined: 01 Apr 2008
Posts: 872

Kudos [?]: 869 [1], given: 18

Name: Ronak Amin
Schools: IIM Lucknow (IPMX) - Class of 2014

### Show Tags

02 Oct 2009, 02:49
1
KUDOS
andrewng wrote:
Is |xy| + xy <= 0?

1/ |x| + xy <= 0
2/ |y| + xy <= 0

IMO D.

This was a killer for me.

Basically the question is asking : Is |xy| + xy = 0, i.e. is xy < 0 ?
This is because, |xy| + xy can only be >=0, it cannot be < 0.

stmt 1.
If x is -ve, -x + xy <= 0 => -x <= -xy => x >= xy => 1 <= y , so y is +ve.
hence, xy < 0.

If x is +ve, x <= -xy => 1 <= -y => -1 >= y , so y is -ve.
hence, xy < 0.

Sufficient.

Similar reasoning for stmt2 by taking y<0 and y>0.

Last edited by Economist on 02 Oct 2009, 04:17, edited 1 time in total.

Kudos [?]: 869 [1], given: 18

Intern
Joined: 30 Aug 2009
Posts: 12

Kudos [?]: [0], given: 0

### Show Tags

02 Oct 2009, 03:22
Agree.

Its D.
The question basically is whether XY=+ve?
Both are sufficient.

Kudos [?]: [0], given: 0

Intern
Joined: 29 Sep 2009
Posts: 16

Kudos [?]: 36 [0], given: 3

### Show Tags

02 Oct 2009, 04:12
Economist wrote:
andrewng wrote:
Is |xy| + xy <= 0?

1/ |x| + xy <= 0
2/ |y| + xy <= 0

IMO D.

This was a killer for me.

Basically the question is asking : Is |xy| + xy = 0, i.e. is xy < 0 ?
This is because, |xy| + xy can only be >=0, it cannot be < 0.

stmt 1.
If x is -ve, -x + xy <= 0 => -x <= -xy => x >= xy => 1 <= y , so y is +ve.
hence, xy < 0.

If x is +ve, x <= -xy => 1 <= -y => -1 >= y , so y is -ve.
hence, xy < 0.

Sufficient.

Similar reasoning for stmt2 by taking y<0 and y>0.

Brilliant!!! You deserve 1 Kudo.

Thanks

Kudos [?]: 36 [0], given: 3

Director
Joined: 01 Apr 2008
Posts: 872

Kudos [?]: 869 [0], given: 18

Name: Ronak Amin
Schools: IIM Lucknow (IPMX) - Class of 2014

### Show Tags

02 Oct 2009, 04:18
Thanks andrewng:) btw what is the source?

Kudos [?]: 869 [0], given: 18

Intern
Joined: 29 Sep 2009
Posts: 16

Kudos [?]: 36 [0], given: 3

### Show Tags

02 Oct 2009, 05:24
Economist wrote:
Thanks andrewng:) btw what is the source?

It's from Manhattan archive!

Kudos [?]: 36 [0], given: 3

Re: Absolute value   [#permalink] 02 Oct 2009, 05:24
Display posts from previous: Sort by