Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Re: Is XYZ an odd number? Where X, Y, Z are positive integers [#permalink]

Show Tags

08 Apr 2010, 11:41

B ? With the second you can know that x must be even so any other two numbers x an even number = even number With the first one you have two option I think: if the primer number is 2 or any other

Re: Is XYZ an odd number? Where X, Y, Z are positive integers [#permalink]

Show Tags

08 Apr 2010, 11:58

IMO E,

2nd statement just give information about X, we need to know primarily the Z. thus not sufficient.

now in statement 1 Any prime number - Z = Positive Odd number

as prime number - any number can be equal to odd number only when:

case 1-- prime number is 2...then 2-z = +ve odd number only when z=1 case 2-- prime number other than 2.....say 7 -z = odd then z must be even.... thus this is also not sufficient.

even if you combine no success..thus E
_________________

Re: Is XYZ an odd number? Where X, Y, Z are positive integers [#permalink]

Show Tags

08 Apr 2010, 14:31

Hi gurpreetsingh, can you please explain more why 2) is INSUF

Quote:

Is XYZ an odd number? Where X, Y, Z are positive integers Such that XYZ is not divisible by 4 and X>Y>Z

1) Any prime number - Z = Positive Odd number 2) X +1 = Prime

Since X is the biggest numbers, x can be 2, in this case 2>1>0 and 2x1x0 = 0 = even or if x is other number for example 10 10+1 = 11 prime number xyz = 10yz = even*number = even

but x cannot be 1 because if x= 1 y must be 0 and z = -1 since x>y>z and all must be positive integers so I think that xyz should be even

any ideas? something wrong in my way of thinking? thanks!

Re: Is XYZ an odd number? Where X, Y, Z are positive integers [#permalink]

Show Tags

08 Apr 2010, 19:16

I am considering XYZ as X*Y*Z.

From the question stem, X,Y,Z are positive integers and X>Y>Z. Inference: XYZ is not divisible by 4 => XYZ do not have two even numbers, either it should be 1 even and two odd numbers or three odd numbers. Statement 1: Any prime - Z = positive odd number, So it shows Z is an even number. ( we can exclude 2 as a prime number in this situation because,the statements says it is any prime, all other primes are odd except 2)

From inference, Because Z is even, the only other possibility for XYZ is to have two odd numbers X, Y. odd*odd*even = even Sufficient

Statement 2: X +1 = Prime Because X>Y>Z and all are +ve integers, X should be greater than 1. X should be an even number to make X+1 as prime number (odd).

From inference, because X is even the only other possibility for XYZ is to have two odd numbers Y,Z. even*odd*odd = even Sufficient

Re: Is XYZ an odd number? Where X, Y, Z are positive integers [#permalink]

Show Tags

09 Apr 2010, 05:50

Hi,

I am also considering XYZ as X*Y*Z.

From the question stem: 1) X,Y,Z are positive integers so 1,2,3 .... 1000000 2) X>Y>Z so X>Y>Z>0 3) XYZ is not divisible by 4, so XYZ is not a multiple of 4 or XYZ do not have two even numbers (two 2)

The real question is whether XYZ contain a 2 or is even ?

Statement 2: 2) X + 1 = Prime Prime: 2,3,5,7,11,... X could be 1,2,6,10 but as we know that X>Y>Z>0 then X can not be equal to 1, then X is even Sufficient

1) Any prime number - Z = Positive Odd number Prime Odd number: 3,5,7,11,... Prime number: 2,3,5,7,11,...

Z is positive from question stem. If prime number = 2 -> 2-Z = positive odd number then Z = 1 If prime number = 3,5,7,11 -> 3 - Z = positive odd number then Z = 2 or a multiple of 2 Insufficient

Re: Is XYZ an odd number? Where X, Y, Z are positive integers [#permalink]

Show Tags

09 Apr 2010, 06:17

Sorry guys, I think I was wrong in exclding 2 for statement 1. If we consider 2 also then for the first statement will give us two answers and so it is Insufficient.

Re: Is XYZ an odd number? Where X, Y, Z are positive integers [#permalink]

Show Tags

21 Nov 2016, 02:22

Hi Everyone. I just Formatted the Question to make it slightly more pleasing to the Eye

Heres my solution here we are given that x,y,z are all >0 and integers with x>y>z We need to check if xyz is odd or not

Statement 1 Here using test cases Let z=1 x=10 y=9 hence xyz is even let z=1 x=9 y=7 hence xyz sill be odd Clearly not sufficient

Statement 2 Here the least value of x is 3 as x>y>z and all are positive integers hence x+1=> prime number >4 Since all the prime number greater than 4 are odd hence x+1=> odd so x=> odd-1=> even Hence xyz will always be even

hence B
_________________

Give me a hell yeah ...!!!!!

gmatclubot

Re: Is XYZ an odd number? Where X, Y, Z are positive integers
[#permalink]
21 Nov 2016, 02:22