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Is y>0?

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Math Expert
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Joined: 02 Sep 2009
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Kudos [?]: 135541 [0], given: 12697

Is y>0? [#permalink]

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New post 21 Aug 2017, 20:49
Expert's post
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A
B
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D
E

Difficulty:

  65% (hard)

Question Stats:

65% (00:48) correct 35% (01:03) wrong based on 39 sessions

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Kudos [?]: 135541 [0], given: 12697

Director
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Is y>0? [#permalink]

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New post 21 Aug 2017, 21:56
Bunuel wrote:
Is y>0?

(1) x^2−y^2=0

(2) x^2+y^2=0


(1) no information about x hence not sufficient

(2) only possible when x=y=0

Sufficient
B

P.S. Second attempt
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Thanks
Luckisnoexcuse


Last edited by Luckisnoexcuse on 21 Aug 2017, 22:23, edited 1 time in total.

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Is y>0? [#permalink]

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New post 21 Aug 2017, 22:20
Answer is B.

statement 1: x^2-y^2=0; x^2=y^2. there can be infinite numbers where x=y, satisfying statement 1. INSUFFICIENT.

statement 2: x^+y^2=0; x^2=-y^2. as this can never be true except x=y=0 (as square of a number cannot be negative). So we have a definite answer i.e. no. SUFFICIENT.

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Swapnil Varshney

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Re: Is y>0? [#permalink]

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New post 22 Aug 2017, 05:43
Is y>0?

(1) x^2−y^2=0

(2) x^2+y^2=0



statement 1

x^2−y^2=0
x^2−y^2 => ( x+y ) ( x-y ) = 0

x+y = 0 and x-y = 0
x = -y and x = y ( no information about x and y ) Insuff.

statement 2

x^2+y^2=0

Now, one thing we know from here that x^2 will always be positive and y^2 will always be positive
So, Sum of two positives can only be zero if both of them are zero.
Hence sufficient . y = 0

Regards

SandySilva
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Re: Is y>0?   [#permalink] 22 Aug 2017, 05:43
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