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Isosceles right triangle with perimeter 16+16(2^0.5). What [#permalink]

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19 Oct 2006, 22:30

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Isosceles right triangle with perimeter 16+16(2^0.5). What is the length of the hypothenuse?

I know this is a special triangle and therefore the sides are in a ratio of 1:1:2^0.5 but I am having a hard time setting this up. The official answer is 16...how do you get there?

Isosceles right triangle with perimeter 16+16(2^0.5). What is the length of the hypothenuse?

I know this is a special triangle and therefore the sides are in a ratio of 1:1:2^0.5 but I am having a hard time setting this up. The official answer is 16...how do you get there?

Thak you very much,

Primeminister

You must remember that the sum of two sides of the triangle cannot be larger than the length of one of the sides....

Therefore, if the perimeter of isoscles triangle is 16+16(2^0.5)... hypotenuse must be equal 16, because the other two sides are equal in legth and the sum of those two sides must be larger than the remaining side....

Thanks SimaQ...i follow the triangle logic of what you said...not sure how that makes the hypothenuse 16 just by looking at the 16+16(2^0.5)??? Perhaps you can set it up in an equation so I can see it.

I can do the following:
x+x+x(2^0.5)=16+16(2^0.5) Solving for x is very easy if you have a calculator and it gets the right answer. A bit tougher doing it just with a pencil.

Perimeter: 16+16(2^0.5).....
From stem we know that the two sides are eqaul....
From the rule above we know that those two sides cannot be equall to 8+8=16, because the remaining side, that is hypotenuse, would be equal to more than 16, that is 16(2^0.5)....

Therefore the sum of the other two sides must be equal to 16(2^0.5)
And the remaining side, hypotenuse, 16....

Just multiply sqrt(2) to your special triangle:
1:1:sqrt(2)
You get
sqrt(2):sqrt(2):2
which gives you perimeter 2+2sqrt(2)
Now you know the ratio is 2:2+2aqrt(2) or 16:16+16sqrt(2).
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