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It takes 50 seconds, 60 seconds, and 100 seconds, 3 pumps A, B, and C

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It takes 50 seconds, 60 seconds, and 100 seconds, 3 pumps A, B, and C  [#permalink]

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New post Updated on: 14 Aug 2017, 21:34
1
4
00:00
A
B
C
D
E

Difficulty:

  15% (low)

Question Stats:

81% (02:34) correct 19% (02:26) wrong based on 89 sessions

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It takes 50 seconds, 60 seconds, and 100 seconds, 3 pumps A, B, and C to pour 100 gallons water into a certain lake at their constant rates, respectively. How many seconds it takes 3 pumps to pour 1,000 gallons water into the lake together at their constant rates, approximately, in seconds?

A. 188
B. 194
C. 214
D. 232
E. 241

Originally posted by Bounce1987 on 14 Aug 2017, 15:30.
Last edited by Bunuel on 14 Aug 2017, 21:34, edited 1 time in total.
Renamed the topic and edited the question.
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Re: It takes 50 seconds, 60 seconds, and 100 seconds, 3 pumps A, B, and C  [#permalink]

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New post 14 Aug 2017, 16:40
1
Bounce1987 wrote:
It takes 50 seconds, 60 seconds, and 100 seconds, 3 pumps A, B, and C to pour 100 gallons water into a certain lake at their constant rates, respectively. How many seconds it takes 3 pumps to pour 1,000 gallons water into the lake together at their constant rates, approximately, in seconds?
A. 188 B. 194 C. 214 D. 232 E. 241

These numbers are huge. Reduce before adding.

Pump A rate = \(\frac{100gal}{50secs}\) = \(\frac{2 gal}{1sec}\)

Pump B rate = \(\frac{100gal}{60secs}\) =\(\frac{\frac{5}{3}gal}{1sec}\)

Pump C rate = \(\frac{100gal}{100secs}\) = \(\frac{1gal}{1sec}\)

ADD numerator of rates (same denominator, 1 sec):
2 + \(\frac{5}{3}\) + 1 =\(\frac{\frac{14}{3}gal}{1sec}\)

W/r = t

\(\frac{1,000}{\frac{14}{3}}\)= (1,000 * \(\frac{3}{14}\)) = \(\frac{1,500}{7}\)

Approximately 214 seconds

Answer C
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Re: It takes 50 seconds, 60 seconds, and 100 seconds, 3 pumps A, B, and C  [#permalink]

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New post 20 Feb 2019, 15:01
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Re: It takes 50 seconds, 60 seconds, and 100 seconds, 3 pumps A, B, and C   [#permalink] 20 Feb 2019, 15:01
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