Rate of Computer A = \(\frac{1}{36}\)

Rate of Computer B = \(\frac{1}{12}\)

\(\frac{1}{2}\) Job completed by Computer A alone; means time consumed by Computer A \(= \frac{1}{2} * 36 = 18\) Hrs

Combined rate of A & B \(= (\frac{1}{36} + \frac{1}{12}) = \frac{1}{9}\)

Time required to complete remaining \(\frac{1}{2}\) Job \(= \frac{1}{2} * \frac{9}{1} = 4.5 Hrs\)

Total Time required to complete job = 18 + 4.5 = 22.5 Hrs

24 Hrs is SAME TIME next day, so 22.5 Hrs would be

7PM Tuesday - 1.5 Hrs = 5:30 PM Tuesday

Answer = B

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