Jacob purchased 7 chocolates, price of each of these 7 chocolates is a

Say, x is price of the cheapest chocolate and x is an integer.

Given, the price of the most expensive chocolate is 4 cents more than 4 times the price of the cheapest chocolate.
Or, the price of the most expensive chocolate=4x+4
To find:- 4x+4=?

Observation:- Eliminate the answer options A,B, and D as these aren't in the form of 4x+4.

Option-C:-
4x+4=24, hence x=5
So, the set of price of chocolates could be: {5,6,7,20,21,22,24}
Keep it.

Option E:- Price of chocolate more than 25, in the form 4x+4 is 28. Or, x=6
Price of the 7 chocolates :-
6, a, b, 20, c, d,28
Since 28 is the maximum value, hence
1) a and b has to be minimum ,distinct, greater than 'x' , and less than the median value.
2) c and d has to be minimum ,distinct, less than '4x+4', and greater than median.
So, a and b could be 7 and 8 respectively.
& c and d could be 21 and 22 respectively.
Hence, total price of chocolates=6+7+8+20+21+22+28=112
Given, Total price of the chocolates=Average price*7=15*7=105
So, the price of the most expensive chocolate can't be more than 25. Eliminate E.

Ans. (C)