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Jason drives to his parents' house and back home the same way. On the

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Jason drives to his parents' house and back home the same way. On the  [#permalink]

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New post 20 Sep 2016, 07:48
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Jason drives to his parents' house and back home the same way. On the way to his parents' house, his speed is 10 kilometers per hour slower than his speed on his way back, and therefore it takes him 20 minutes longer. If Jason drives to his parents' house at 50 kilometers per hour, how many minutes does he spend on his way back from his parents' house?

A. 60
B. 80
C. 100
D. 120
E. 150

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Jason drives to his parents' house and back home the same way. On the  [#permalink]

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New post 20 Sep 2016, 09:25
C

since distance will be same we have to just equate D=S x T

on his way to parent's house S-10 x (T+20) since it takes 20 min lobger if he travels 10 km/hr slower.

on his way back S x T.

Just equate these two as distance is same and value of S-10=50 you will get your T
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Re: Jason drives to his parents' house and back home the same way. On the  [#permalink]

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New post 20 Sep 2016, 09:31
on simplifying (x-10)(t+20) = xt
20x-10t = 200

x = 50 substituting x = 50, we get 100-20 = t

t = 80

Option B

Correct me if i am wrong
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Re: Jason drives to his parents' house and back home the same way. On the  [#permalink]

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New post 20 Sep 2016, 09:39
x-10 is 50 not x

since 50 is his speed when he goes to his parent's place so on th way back it will be 60 :)
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Jason drives to his parents' house and back home the same way. On the  [#permalink]

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New post 20 Sep 2016, 12:48
Jason drives to his parents' house and back home the same way. On the way to his parents' house, his speed is 10 kilometers per hour slower than his speed on his way back, and therefore it takes him 20 minutes longer. If Jason drives to his parents' house at 50 kilometers per hour, how many minutes does he spend on his way back from his parents' house?

A. 60
B. 80
C. 100
D. 120
E. 150

let t=return time
50(t+1/3)=60t
t=1 2/3 hours=100 minutes
C.
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Re: Jason drives to his parents' house and back home the same way. On the  [#permalink]

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New post 20 Sep 2016, 21:13
C.

50(t+20) = 60t

T=100

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Re: Jason drives to his parents' house and back home the same way. On the  [#permalink]

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New post 20 Sep 2016, 22:22
Bunuel wrote:
Jason drives to his parents' house and back home the same way. On the way to his parents' house, his speed is 10 kilometers per hour slower than his speed on his way back, and therefore it takes him 20 minutes longer. If Jason drives to his parents' house at 50 kilometers per hour, how many minutes does he spend on his way back from his parents' house?

A. 60
B. 80
C. 100
D. 120
E. 150



Speed on way to parents house 50.... so time taken is x/50 where x is the distance..
On way back it is x/(50+10)=x/60..
So x/50 -x/60 =1/3....x/300=1/3..x=100km...
Time on way back = 100/60 hr or 100*60/60=100 minutes
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Jason drives to his parents' house and back home the same way. On the  [#permalink]

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New post 21 Sep 2016, 18:58
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\(60T = D\)
\(50 * (T+ \frac{1}{3}) = D\)

\(60T = 50T + \frac{50}{3}\)
\(10T = \frac{50}{3}\)
\(T = \frac{5}{3}\) hours
100 minutes

IMO C
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Re: Jason drives to his parents' house and back home the same way. On the  [#permalink]

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New post 27 Oct 2018, 11:59
distance is same so
50*t=60(t-20)
t=120
for back from his parents' house
t=100
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Re: Jason drives to his parents' house and back home the same way. On the &nbs [#permalink] 27 Oct 2018, 11:59
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