Hi
Bunuel,
callmeDP could you please help[/quote]
Sure, lets see. There are many ways to solve this mate, below is one way
Distance travelled by Jerry= 2000 m
And by jim = 1800
Let time taken by jerry is = T min
Then time taken by jim is = T + 1/2 min
Similarly, for second trip
Distance travelled by Jerry = 1000 m
And by jim = 2000
Time taken by jerry = T1 min
Time taken by jim = T1 + 3 min
Now you know their speed will remain same in both first and second trip.
Speed of Jerry = 1000/T1 = 2000/T
Solving, 2*T1 = T
Speed of jim = 2000/T1 + 3 = 1800/ T + 0.5
Solving, 10/T1+3 = 9/T+0.5
Substitute, 2*T1 = T
10*(2*T1 + 3) = 9*(T1 + 3)
T1 = 2 min
T = 2*T1 = 2*2 = 4 min
Speed of Jerry = 2000/4 = 500 m/min
Jim = 1800/4+0.5 = 400 m/min
Time taken to complete 2000 m
Time taken by jerry = 2000/ 500 = 4 minutes
Time taken by jim = 2000 / 400 = 5 minutes
Ans B
Let me know if this helps,
carouselambraPosted from my mobile device[/quote]
Hi,
Liked the approach. However, have a silly question.
As per your calculation,
Time taken by jerry = T1 min
Time taken by jim = T1 + 3 min
But in the question, it is stated that
"Jerry gives Jim a start of 3mins and is beaten by 1000m"Would this not mean that the total time taken by Jerry t+3 because he lost the race? Jerry should be t.
Or, total time taken by Jim= t-3 and Jerry=t
What is the issue with this? Thanks in advance!