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# Joe sells twice as many $10 tickets as Sue and Sue sells  post reply Question banks Downloads My Bookmarks Reviews Important topics Author Message Senior Manager Joined: 02 Oct 2005 Posts: 297 Joe sells twice as many$10 tickets as Sue and Sue sells [#permalink]

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09 Nov 2005, 10:42
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Joe sells twice as many $10 tickets as Sue and Sue sells three times as many$5 tickets as Joe. How many tickets did Joe sell? (tickets only come in $10 or$5)
(1) Sue sold a total of 35 tickets.
y = number of $5 tickets Joe sold given: joe sold: 2x + y tickets Sue sold: x + 3y tickets we need to find 2x+y (1) x + 3y = 35 cannot get anything. two variables one equation. (2) gives two equations: 3x + 4y = 70 30x + 20y = 500 solve for x,y and get 2x+y I was thinking C. But you are correct. Answer has to be (b). I did not realize that you can form an equation out of the total sales. Senior Manager Joined: 02 Oct 2005 Posts: 297 ### Show Tags 09 Nov 2005, 21:03 Thats correct, OA is B. I was about to choose C, but then thought about the available option again and found the answer to be B. Just wanted to post it so that forum members does not fall for the wrong answer. Senior Manager Joined: 07 Jul 2005 Posts: 402 ### Show Tags 09 Nov 2005, 21:20 (1) Insufficient. We get only 3 equations, but we have 4 unknowns (2) Sufficient. We have 4 equations and 4 unknowns. I pick B. 09 Nov 2005, 21:20 Display posts from previous: Sort by # Joe sells twice as many$10 tickets as Sue and Sue sells

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