John is one year older than three times Linda's age. If their ages

John is one year older than three times Linda's age in years:
J = 3L + 1

Currently, their ages add up to 33:
J + L = 33

(3L + 1) + L = 33
4L = 32
L = 8

Linda is 8 years old. John, from first equation, is
3L + 1
3(8) + 1 = 25

John is 25 years old now. In four years he will be 29.

Answer C
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Let present age of John= J
......................... Linda=L

As per statement
J+L= 33------(1)
J= 3L+1------(2)

Solving (1) and (2)
L= 8 and J= 25

Present age of John= 25 years and after 4 years it will be 25+4= 29 years

Answer: C.

We can let John’s current age = J and Linda’s current age = L and create the following equations:

J = 1 + 3L

and

J + L = 33

Thus:

1 + 3L + L = 33

4L = 32

L = 8, so J = 25. So, in 4 years, John will be 29.

Answer: C
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Hi All,

We're told that John is one year older than three times Linda's age, and the sum of their ages is 33 years. We're asked for John's age in 4 YEARS.

There are a couple of different ways to approach this question - since the answer choices are relatively small, you can actually use some 'brute force' arithmetic and get the correct answer without too much trouble:

IF...
Linda is 1, then John is 4 and the total is 5
Linda is 2, then John is 7 and the total is 9
Linda is 3, then John is 10 and the total is 13

Notice how the total age increases by 4 years each time... getting from a total of 13 years to a total of 33 years shouldn't be too tough (it's just 5 more 'steps'):
Linda is 8, then John is 25 and the total is 33

Thus, in 4 years, John will be 25+4 = 29

Final Answer:

GMAT assassins aren't born, they're made,
Rich