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Joshua and Jose work at an auto repair center with 4 other

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Re: Joshua and Jose work at an auto repair center with 4 other  [#permalink]

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New post 31 Mar 2015, 02:30
aiming700plus wrote:
Joshua and Jose work at an auto repair center with 4 other workers. For a survey on health care insurance, 2 of the 6 workers will be randomly chosen to be interviewed. What is the probability that Joshua and Jose will both be chosen?

A. 1/15
B. 1/12
C. 1/9
D. 1/6
E. 1/3


No. of ways in which Joshua and Jose can be chosen out of 2 people = 2C2 = 1
No. of ways in which Joshua and Jose can be chosen out of 6 people = 6C2 = 15
Required probability = 1/15

Hence option (A).

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Re: Joshua and Jose work at an auto repair center with 4 other  [#permalink]

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New post 15 Sep 2017, 12:27
Hi - why doesnt the following work

(1/6) * (1/5) = 1/30

just wondering why this didnt work ...
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Re: Joshua and Jose work at an auto repair center with 4 other  [#permalink]

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New post 16 Sep 2017, 04:24
jabhatta@umail.iu.edu wrote:
Hi - why doesnt the following work

(1/6) * (1/5) = 1/30

just wondering why this didnt work ...


What is the logic behind this?

If you say that 1/6 is the probability of choosing Joshua first and 1/5 is the probability of choosing Jose second, then you are missing a case when you are choosing Jose first and Joshua second, so 1/6*1/5 + 1/6*1/5 = 1/15.
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Re: Joshua and Jose work at an auto repair center with 4 other  [#permalink]

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New post 16 Sep 2017, 10:21
Total combinations = 6C2 = 15
Only 1 our of this combination will have Joshua and Jose both chosen = 1
Probability = 1/15
Hence A
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Re: Joshua and Jose work at an auto repair center with 4 other  [#permalink]

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New post 16 Sep 2017, 11:56
2x1/6x1/5 = 1/15
Joshua chosen first and then Jose and Viz.
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Re: Joshua and Jose work at an auto repair center with 4 other  [#permalink]

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New post 13 May 2019, 11:38
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aiming700plus wrote:
Joshua and Jose work at an auto repair center with 4 other workers. For a survey on health care insurance, 2 of the 6 workers will be randomly chosen to be interviewed. What is the probability that Joshua and Jose will both be chosen?

A. 1/15
B. 1/12
C. 1/9
D. 1/6
E. 1/3


P(Joshua and Jose both chosen) = P(one of the two men is chosen first AND the other man is chosen second)
= P(one of the two men is chosen first) x P(the other man is chosen second)
= 2/6 x 1/5
= 1/15

Answer: A

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Re: GMAT prep II - probability question  [#permalink]

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New post 14 Oct 2019, 06:02
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Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: GMAT prep II - probability question   [#permalink] 14 Oct 2019, 06:02

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