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# Judy ran along the fence that surrounds her house. The fence forms a

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Math Expert
Joined: 02 Sep 2009
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Judy ran along the fence that surrounds her house. The fence forms a  [#permalink]

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18 Sep 2016, 08:54
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Difficulty:

15% (low)

Question Stats:

83% (01:30) correct 17% (01:50) wrong based on 149 sessions

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Judy ran along the fence that surrounds her house. The fence forms a rectangle whose dimensions are 20×30 meters. Beginning from a vertex of the rectangle, Judy started running along one of the long sides, and stopped when she had completed running along 7 sides. This jog took her 30 seconds. What was Judy's speed in meters per second?

A. 2/3
B. 8/3
C. 23 1/3
D. 17/3
E. 6

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Re: Judy ran along the fence that surrounds her house. The fence forms a  [#permalink]

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18 Sep 2016, 17:51
Judy ran 7 sides of the rectangle.
She ran one complete perimeter, then one longer side, shorter side and longer side.

Distance traveled = $$2(30+20) + 30 + 20 + 30.$$
= 180

Speed = $$\frac{Distance}{time}$$
= $$\frac{180}{30}$$
= 6 $$\frac{m}{s}$$
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Re: Judy ran along the fence that surrounds her house. The fence forms a  [#permalink]

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20 Sep 2016, 00:08
4 times is perimeter.
8 times is twice perimeter.
7 times is twice perimeter minus breadth. since, she started her from run from longest side. check this while doing this kinda problems. gmat plays tricks here.
perimeter= 2(l+b) = 100.
twice perimeter= 200. 200-breadth = 180
speed 180/30 = 6.
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Re: Judy ran along the fence that surrounds her house. The fence forms a  [#permalink]

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21 Sep 2016, 19:17
Top Contributor
Total perimeter of the fence is 100m. Starting from the "long" side, that being 30m, the distance ran is one full loop 100m plus three of the four sides 30m + 20m + 30m = 180m. 180m/30s = $$6\frac{m}{s}$$
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Re: Judy ran along the fence that surrounds her house. The fence forms a  [#permalink]

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30 Jan 2018, 10:23
Bunuel wrote:
Judy ran along the fence that surrounds her house. The fence forms a rectangle whose dimensions are 20×30 meters. Beginning from a vertex of the rectangle, Judy started running along one of the long sides, and stopped when she had completed running along 7 sides. This jog took her 30 seconds. What was Judy's speed in meters per second?

A. 2/3
B. 8/3
C. 23 1/3
D. 17/3
E. 6

We see that Judy ran 4 long sides and 3 short sides for a total distance of 4 x 30 + 3 x 20 = 180 meters.

Since it took her 30 seconds her rate is 180/30 = 6 meters/second.

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Re: Judy ran along the fence that surrounds her house. The fence forms a  [#permalink]

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31 Jan 2018, 10:45
Bunuel wrote:
Judy ran along the fence that surrounds her house. The fence forms a rectangle whose dimensions are 20×30 meters. Beginning from a vertex of the rectangle, Judy started running along one of the long sides, and stopped when she had completed running along 7 sides. This jog took her 30 seconds. What was Judy's speed in meters per second?

A. 2/3
B. 8/3
C. 23 1/3
D. 17/3
E. 6

The total distance covered will be -
$$2* 50 + 80 = v * 30$$
$$v = 6 m/sec$$
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Joined: 01 Jan 2017
Posts: 9
Re: Judy ran along the fence that surrounds her house. The fence forms a  [#permalink]

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11 Feb 2018, 22:07
Hi all,

why are we assuming that she runs starting from the longer side?
How do we know this?
If she would start from a small side would it not be:
- Distance: 20+30+20+30 (1 full) +20+30+20 (3 sides) = 170
- Time: 30
- Speed: Distance / Time = 170/30=17/30 Answer C?
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Re: Judy ran along the fence that surrounds her house. The fence forms a  [#permalink]

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11 Feb 2018, 22:21
malcolm123 wrote:
Hi all,

why are we assuming that she runs starting from the longer side?
How do we know this?
If she would start from a small side would it not be:
- Distance: 20+30+20+30 (1 full) +20+30+20 (3 sides) = 170
- Time: 30
- Speed: Distance / Time = 170/30=17/30 Answer C?

Hi malcolm123,

Its mentioned in the question that she starts running along the longer side.
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Re: Judy ran along the fence that surrounds her house. The fence forms a  [#permalink]

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12 Feb 2018, 19:17
rahul16singh28 wrote:
malcolm123 wrote:
Hi all,

why are we assuming that she runs starting from the longer side?
How do we know this?
If she would start from a small side would it not be:
- Distance: 20+30+20+30 (1 full) +20+30+20 (3 sides) = 170
- Time: 30
- Speed: Distance / Time = 170/30=17/30 Answer C?

Hi malcolm123,

Its mentioned in the question that she starts running along the longer side.

Dear rahul16singh28,

thanks a million! Indeed the key to answering all questions is to slowly read the question!

Have a great day,

Malcolm

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Re: Judy ran along the fence that surrounds her house. The fence forms a &nbs [#permalink] 12 Feb 2018, 19:17
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