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Jug contains water and orange juice in the ratio 5:7 . anoth

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Re: Jug contains water and orange juice in the ratio 5:7 . anoth  [#permalink]

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New post 21 Apr 2014, 20:21
Quantity of Orange Juice in

Jug 1 \(= \frac{7}{12}\)

Jug 2 \(= \frac{2}{9}\)

Requirement in the mixture\(= \frac{4}{7}\)

Using Alligation method

\(\frac{\frac{4}{7} - \frac{2}{9}}{\frac{7}{12} - \frac{4}{7}}\)

\(= \frac{88}{3}\)
Answer = C
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Re: Jug contains water and orange juice in the ratio 5:7 . anoth  [#permalink]

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New post 02 May 2014, 02:29
Hello ,

Can someone please show how to do this problem by allegation :?:
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Re: Jug contains water and orange juice in the ratio 5:7 . anoth  [#permalink]

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New post 02 May 2014, 18:08
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gauravsoni wrote:
Hello ,

Can someone please show how to do this problem by allegation :?:


This solution: jug-contains-water-and-orange-juice-in-the-ratio-5-7-anoth-111775.html#p904568
and many others are based on alligation
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Re: Jug contains water and orange juice in the ratio 5:7 . anoth  [#permalink]

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New post 16 Sep 2016, 19:29
My 2 cents:
Mixture 1: w:o = 5:7 => w:t = 5:12
Mixture 2: w:o = 7:2 => w:t = 7:9
Final mixture: w:o = 3:4 => w:t = 3:7
x*(5/12) + (1-x)*(7/9) = 3/7
5x/12 + 7/9 - 7x/9 = 3/7
15x + 28 - 28x/(2*2*3*3) = 3/7
28 - 13x/(2*2*3*3) = 3/7
196 - 91x = 108
88 = 91x
x = 88/91 & (1-x) = 3/91
x:(1-x) = 88:3
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New post 10 Jun 2017, 19:24
rxs0005 wrote:
Jug contains water and orange juice in the ratio 5:7 . another jug contains water and orange juice in ratio 7 : 2 . In what proportion should these 2 liquids be mixed to give a water and orange juice in ratio 3 : 4

A. 4 : 5
B. 85 : 3
C. 88 : 3
D. 2 : 3
E. 87 : 7

1. (Quantity of jug 1)* proportion of water + (Quantity of jug 2)* proportion of water / (Quantity of jug 1)* proportion of juice + (Quantity of jug 2)* proportion of juice = 3/4
2. Let x and y be the quantities in jug 1 and jug 2 resp to get the mixture
3. (x*5/12 + y*7/9) / (x*7/12 + y*2/9) = 3/4
x/y=88/3
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Re: Jug contains water and orange juice in the ratio 5:7 . anoth  [#permalink]

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New post 10 Jun 2017, 21:55
Imo C
Setting up the equation and solving
5x/12+7y/9=3/7(x+y)
We get 88:3

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New post 10 Jun 2017, 22:11
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Ans : C
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Re: Jug contains water and orange juice in the ratio 5:7 . anoth  [#permalink]

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New post 01 Dec 2019, 06:57
VeritasKarishma wrote:
rxs0005 wrote:
Jug contains water and orange juice in the ratio 5:7 . another jug contains water and orange juice in ratio 7 : 2 . In what proportion should these 2 liquids be mixed to give a water and orange juice in ratio 3 : 4


4 : 5

85 : 3

88 : 3

2 : 3

87 : 7


In such questions focus on one thing - either water or orange juice. Let's work with water
Jug1 - Water concentration is 5/12
Jug2 - Water concentration is 7/9
Mixture - Water concentration is 3/7

Now, \(\frac{w1}{w2} = \frac{\frac{7}{9} - \frac{3}{7}}{\frac{3}{7} - \frac{5}{12}} = \frac{88}{3}\)

A detailed explanation of the concept used above is given here:
http://www.veritasprep.com/blog/2011/03 ... -averages/



how do you ascertain when to use this method vs scale method?
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Re: Jug contains water and orange juice in the ratio 5:7 . anoth  [#permalink]

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New post 31 Jan 2020, 20:59
chetan2u, Gladiator59, Bunuel generis VeritasKarishma

While i understood the problem -- i am not sure i even understand what exactly is 88 : 3 ?

Are you saying -- i pour

-- in 88 portions of Jug 1 and 3 portions of Jug 2 -- my resulting new mixture will somehow have a ratio of 3 :4 for water to OJ ?

or

-- in 176 (88*2) portions of Jug 1 and 6 portions (3*2) of Jug 2 -- my resulting new mixture will somehow have a ratio of 3 :4 for water to OJ ?
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Re: Jug contains water and orange juice in the ratio 5:7 . anoth   [#permalink] 31 Jan 2020, 20:59

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