It is currently 21 Oct 2017, 18:37

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Just wanted to know the sufficiency condition for a modulus

Author Message
Manager
Joined: 14 Mar 2007
Posts: 60

Kudos [?]: 1 [0], given: 0

Just wanted to know the sufficiency condition for a modulus [#permalink]

### Show Tags

19 Jul 2007, 10:36
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Just wanted to know the sufficiency condition for a modulus expression to be true.

Is mainly tested in data sufficiency questions.

e.g. Is |x| > 1 ?
In such a case do we need to prove both that (i) when x>0 --> x>1 and (ii) when x<0> x<1>1 OR/AND (ii) x<-1 for proving suffficiency. ??

Thanks a lot for providing clarity

Kudos [?]: 1 [0], given: 0

Director
Joined: 26 Feb 2006
Posts: 900

Kudos [?]: 157 [0], given: 0

Re: Sufficiency condition for a modulus [#permalink]

### Show Tags

19 Jul 2007, 14:13
[quote="ajay_gmat"]Just wanted to know the sufficiency condition for a modulus expression to be true.

Is mainly tested in data sufficiency questions.

e.g. Is |x| > 1 ?
In such a case do we need to prove both that (i) when x>0 --> x>1 and (ii) when x<0> x<1>1 OR/AND (ii) x<1> 1:
Is |x| > 1? yes.

(b) 1>= x >= -1:
Is |x| > 1? no.

(c) x <1> 1? yes.

Kudos [?]: 157 [0], given: 0

Director
Joined: 26 Feb 2006
Posts: 900

Kudos [?]: 157 [0], given: 0

Re: Sufficiency condition for a modulus [#permalink]

### Show Tags

19 Jul 2007, 14:24
This site is crazy. I posted the following on the above post but posted partially (as above):

Quote:
three conditions when:

(a) x > 1:
Is |x| > 1? yes.

(b) 1>= x >= -1:
Is |x| > 1? no.

(c) x <1> 1? yes.

Kudos [?]: 157 [0], given: 0

Manager
Joined: 14 Mar 2007
Posts: 60

Kudos [?]: 1 [0], given: 0

### Show Tags

20 Jul 2007, 02:27
Hi Himalayan,

Thanks for posting the reply.. What i meant was that for proving the modules do we need to have both the condition as true or proving any of the condition as true would help us take that as the answer.

i.e. For |X| > 1

Do we need to prove both that (i) x > 1 (x>0) and (ii) x < -1 (X<0> 1 ..

Hope this clarifies, Thanks

Kudos [?]: 1 [0], given: 0

20 Jul 2007, 02:27
Display posts from previous: Sort by