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K does not equal 0, 1, or -1. Is 1/k > 0? 1) 1/k - 1 >

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K does not equal 0, 1, or -1. Is 1/k > 0? 1) 1/k - 1 > [#permalink]

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15 Jun 2008, 12:35
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

K does not equal 0, 1, or -1. Is 1/k > 0?
1) 1/k - 1 > 0
2) 1/k + 1 > 0
Director
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Re: Is K what I think it is ? [#permalink]

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15 Jun 2008, 13:49
Vavali wrote:
K does not equal 0, 1, or -1. Is 1/k > 0?
1) 1/k - 1 > 0
2) 1/k + 1 > 0

is 1) saying (1/k) - 1 or 1/(k-1) ??

need to sort out those braces varvali
Senior Manager
Joined: 07 Feb 2008
Posts: 313
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Kudos [?]: 145 [0], given: 1

Re: Is K what I think it is ? [#permalink]

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15 Jun 2008, 14:21
Vavali wrote:
K does not equal 0, 1, or -1. Is 1/k > 0?
1) 1/k - 1 > 0
2) 1/k + 1 > 0

is 1) saying (1/k) - 1 or 1/(k-1) ??

need to sort out those braces varvali

Apologies,

1) 1/(k - 1) > 0
2) 1/(k + 1) > 0
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Re: Is K what I think it is ? [#permalink]

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15 Jun 2008, 16:32
1) 1/(k - 1) > 0
From here it follows (k-1)>0 and thus k>1 so 1/k will be > 0 => sufficient

2) 1/(k + 1) > 0
Insuff. k > -1 gives us nothing. If k=-0.5 => 1/k=-2 which is obviously < 0; if k=0.5 1/k=2 > 0.

Thus, A.
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Re: Is K what I think it is ? [#permalink]

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15 Jun 2008, 19:11
I get D!

1. 1/(K-1) > 0

The above inequality says (K-1) = +ve, and K is not equal to -1,0,+1, so K>1

A is sufficient

2. 1/(K+1) > 0

The above inequality says (K+1) = +ve, and K is not equal to -1,0,+1, so K>1

B is sufficient

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Re: Is K what I think it is ? [#permalink]

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15 Jun 2008, 19:23
Vavali wrote:
Vavali wrote:
K does not equal 0, 1, or -1. Is 1/k > 0?
1) 1/k - 1 > 0
2) 1/k + 1 > 0

is 1) saying (1/k) - 1 or 1/(k-1) ??

need to sort out those braces varvali

Apologies,

1) 1/(k - 1) > 0
2) 1/(k + 1) > 0

A.

1)k-1> 0; k>1 ; with given conditions, sufficient.
2)k+1> 0; k>-1; K can have values between 0>k>-1 making it insuff
Senior Manager
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Re: Is K what I think it is ? [#permalink]

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15 Jun 2008, 19:32
Kalyan wrote:
I get D!

1. 1/(K-1) > 0

The above inequality says (K-1) = +ve, and K is not equal to -1,0,+1, so K>1

A is sufficient

2. 1/(K+1) > 0

The above inequality says (K+1) = +ve, and K is not equal to -1,0,+1, so K>1

B is sufficient

question doesnt say that K is an integer so K can assume any values. Hence A.
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Re: Is K what I think it is ? [#permalink]

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16 Jun 2008, 00:45
The OA is A. Thanks guys
Re: Is K what I think it is ?   [#permalink] 16 Jun 2008, 00:45
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