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Kap Advanced 800: Word Problems: # 26 pg 306 [#permalink]

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29 Aug 2006, 09:19

I understand how to solve it by Backsolving. Is there a right straightforward way that doesnâ€™t need to backsolve?

Machine A and Machine B are each used to manufacture 660 sprockets. It takes machine A 10 hours longer to produce 660 sprockets than machine B. Machine B produces 10 percent more sprockets per hour than machine A. How many sprockets per hour does machine A produce?
a. 6
b. 6.6
c. 60
d. 100
e. 110
_________________

Re: Kap Advanced 800: Word Problems: # 26 pg 306 [#permalink]

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27 May 2011, 17:42

Thank you for posting. I was going nuts trying to figure out how to set this problem up. Lame for the book to ignore the actual method for solving. I'm not looking for a cheat here!

Re: Kap Advanced 800: Word Problems: # 26 pg 306 [#permalink]

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03 Jun 2011, 09:46

saumster wrote:

I understand how to solve it by Backsolving. Is there a right straightforward way that doesnâ€™t need to backsolve?

Machine A and Machine B are each used to manufacture 660 sprockets. It takes machine A 10 hours longer to produce 660 sprockets than machine B. Machine B produces 10 percent more sprockets per hour than machine A. How many sprockets per hour does machine A produce? a. 6 b. 6.6 c. 60 d. 100 e. 110

here is one way to solve this problem

Suppose

Work rate of machine a is y spockets per hour( produces y spockets per hour) then work rate of Machine B is 1.1y spockets/ hr

then no. of hours req. to produce 660 spockets by machine then time taken by machine B = 660/1.1y

then time taken by machine A to produce 660 spockets= 660/1.1y + 10

660/y=660/1.1y + 10

660/y* (1-10/11)=10

660/y* 1/11=10

=> y= 6

so machine A produces 6 spockets per hour
_________________

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