GMAT Question of the Day: Daily via email | Daily via Instagram New to GMAT Club? Watch this Video

 It is currently 29 Jan 2020, 06:20

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Karen travelled x miles from her home to office, at a speed of y miles

Author Message
TAGS:

### Hide Tags

Director
Joined: 07 Mar 2019
Posts: 611
Location: India
GMAT 1: 580 Q43 V27
WE: Sales (Energy and Utilities)
Karen travelled x miles from her home to office, at a speed of y miles  [#permalink]

### Show Tags

02 Dec 2019, 06:46
1
1
00:00

Difficulty:

95% (hard)

Question Stats:

41% (03:14) correct 59% (03:34) wrong based on 37 sessions

### HideShow timer Statistics

Karen travelled x miles from her home to office, at a speed of y miles per hour and on her way back, she takes the same route, and travels for 10 miles at a speed of y miles per hour before stopping for an hour. Now, by what percentage should she increase her speed so that the overall time taken to reach back home from the office is the same as that taken to reach the office from home?

a. $$\frac{(x−10)×100y}{x−y−10 }$$

b. $$\frac{100y}{x−y−10}$$

c. $$\frac{100x}{y−x−10}$$

d. $$\frac{(x−10)×100y}{y−x−10}$$

e. $$\frac{100y}{y−x−10}$$

_________________
Ephemeral Epiphany..!

GMATPREP1 590(Q48,V23) March 6, 2019
GMATPREP2 610(Q44,V29) June 10, 2019
GMATPREPSoft1 680(Q48,V35) June 26, 2019
Math Expert
Joined: 02 Aug 2009
Posts: 8322
Karen travelled x miles from her home to office, at a speed of y miles  [#permalink]

### Show Tags

02 Dec 2019, 20:17
1
1
lnm87 wrote:
Karen travelled x miles from her home to office, at a speed of y miles per hour and on her way back, she takes the same route, and travels for 10 miles at a speed of y miles per hour before stopping for an hour. Now, by what percentage should she increase her speed so that the overall time taken to reach back home from the office is the same as that taken to reach the office from home?

a. $$\frac{(x−10)×100y}{x−y−10 }$$

b. $$\frac{100y}{x−y−10}$$

c. $$\frac{100x}{y−x−10}$$

d. $$\frac{(x−10)×100y}{y−x−10}$$

e. $$\frac{100y}{y−x−10}$$

A simple way would be to take values for x and y

Let x=40 miles and y=5.... time taken while goons =40/5=8
Now while coming back
10 miles at 5 mph means 10/5 or 2 hrs. One hour break, adding up to 3 hrs
So now he has to cover 40-10=30 miles in 5 hrs. Speed =30/5=6 mph

Change in speed (6-5)/5*100=100/5=20%

Check choices
B. 100y/(x-y-10)=100*5/(40-5-10)=500/25=20%

B
_________________
Senior Manager
Joined: 16 Feb 2015
Posts: 283
Location: United States
Concentration: Finance, Operations
Karen travelled x miles from her home to office, at a speed of y miles  [#permalink]

### Show Tags

03 Dec 2019, 22:25
chetan2u wrote:
lnm87 wrote:
Karen travelled x miles from her home to office, at a speed of y miles per hour and on her way back, she takes the same route, and travels for 10 miles at a speed of y miles per hour before stopping for an hour. Now, by what percentage should she increase her speed so that the overall time taken to reach back home from the office is the same as that taken to reach the office from home?

a. $$\frac{(x−10)×100y}{x−y−10 }$$

b. $$\frac{100y}{x−y−10}$$

c. $$\frac{100x}{y−x−10}$$

d. $$\frac{(x−10)×100y}{y−x−10}$$

e. $$\frac{100y}{y−x−10}$$

A simple way would be to take values for x and y

Let x=40 miles and y=5.... time taken while goons =40/5=8
Now while coming back
10 miles at 5 mph means 10/5 or 2 hrs. One hour break, adding up to 3 hrs
So now he has to cover 40-10=30 miles in 5 hrs. Speed =30/5=6 mph

Change in speed (6-5)/5*100=100/5=20%

Check choices
B. 100y/(x-y-10)=100*5/(40-5-10)=500/25=20%

B

Dear chetan2u

By this approach, it will be very time consuming during exam.
As Firstly we have to suppose the values & then find solutions
Then putting values in options for same result.
It will take around 3-4mins to solve by this method,& during GMAT Exam, it will be difficult to solve in time.

Is there any other approach?
Director
Joined: 07 Mar 2019
Posts: 611
Location: India
GMAT 1: 580 Q43 V27
WE: Sales (Energy and Utilities)
Re: Karen travelled x miles from her home to office, at a speed of y miles  [#permalink]

### Show Tags

04 Dec 2019, 00:00
rajatchopra1994 wrote:
Dear chetan2u

By this approach, it will be very time consuming during exam.
As Firstly we have to suppose the values & then find solutions
Then putting values in options for same result.
It will take around 3-4mins to solve by this method,& during GMAT Exam, it will be difficult to solve in time.

Is there any other approach?

The other way is to solve with variables - straight forward one. But it is not something that one can avert mistakes.
Ans yes it time consuming as well...
_________________
Ephemeral Epiphany..!

GMATPREP1 590(Q48,V23) March 6, 2019
GMATPREP2 610(Q44,V29) June 10, 2019
GMATPREPSoft1 680(Q48,V35) June 26, 2019
CrackVerbal Quant Expert
Joined: 12 Apr 2019
Posts: 369
Re: Karen travelled x miles from her home to office, at a speed of y miles  [#permalink]

### Show Tags

04 Dec 2019, 03:59
1
IN questions like these on the GMAT, the Algebraic approach would only do one thing – put you at a disadvantage in terms of time taken to solve the question. The best approach to solve this question within 2 minutes (or at least close to) is to plug in simple values for the unknowns.

Let’s take x as 100 miles and y as 10 miles per hour. This means that she takes 10 hours to reach her office from her home.

On her way home, she travels for 10 miles at the same speed. This means she’s spent one hour travelling this distance. She then stops for one hour. This means that she will have to travel the remaining 90 miles in the remaining 8 hours since the total time has to be the same in both the onward and return journeys. This works out to an average speed of 11.25 miles per hour for this segment.
Compared to her original speed of 10 miles per hour, this is a percentage increase of 12.5%. Now, the only thing left is to find the option that gives us this percentage change.

Observing the options, we see that the denominator is either (x-y-10) or (y-x-10). Remember that y is going to be smaller than x and hence (y-x-10) will turn out to be negative. Since there has to be a percentage increase in the speed (remember, the average speed has to increase to maintain the time), we can’t have negative values.

Therefore, we eliminate all options that have (y-x-10) as the denominator. Options C, D and E can be eliminated. The possible answer options are A or B.

Answer option A has a substantially large numerator for us to consider that as a logical percentage increase. Substituting the values of x and y in answer option B, we see that
$$\frac{{100y} }{ {(x-y-10)}}$$ = $$\frac{{100 * 10} }{ {100-10-10}}$$ = 1000/80 = 12.5.

This is the number we were looking for. We can conclusively rule out option A now. The correct answer option is B.

A point to note is that you will have to practice the plugging in and elimination strategies regularly when you are preparing for the GMAT. Only then will you have the confidence to use it on the actual test. Also remember that GMAT is not a test of your math skills alone, your reasoning and logical skills are tested too. Considering this, if you always take recourse to traditional methods of problem solving in Quant, you’d be a one-dimensional problem solver. That’s not what any of us want to be on the GMAT.

Hope that helps!
_________________
Re: Karen travelled x miles from her home to office, at a speed of y miles   [#permalink] 04 Dec 2019, 03:59
Display posts from previous: Sort by