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Last Sunday a certain store sold copies of Newspaper A for

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Re: Last Sunday a certain store sold copies of Newspaper A for  [#permalink]

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New post 13 Jun 2018, 13:26
Bunuel Can you please check if my approach is correct:

Assumption: I have assumed P= 50% and the total copies sold as 200.


Therefore Revenue from A= 1*100 =100 and B=1.25*100=125.
Total revenue= 225

Hence r= (100/225)* 100 =400/9.

If we plug in P=50 in all the options only D gives the answer.
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Re: Last Sunday a certain store sold copies of Newspaper A for  [#permalink]

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New post 19 Jun 2018, 23:00
I fount it easy to plug some very simple numbers:
Let the store sold 1 newspaper type A and 0 newspaper type B.
it means that r=100 p=100
Test the questions, only D satisfies.

Good-bey to complex algebra equations
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Re: Last Sunday a certain store sold copies of Newspaper A for  [#permalink]

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New post 30 Jun 2018, 09:54
VeritasPrepKarishma wrote:
stampap wrote:
the question mentions news papers of A and (copies) of newspapers of A , where do we count B? i got really confused with this question please help


Note what the question says:

"If r percent of the store’s revenues from newspaper sales was from Newspaper A and if p percent of the newspapers that the store sold were copies of newspaper A, which of the following expresses r in terms of p?"

r% of the revenue is from A
p% of the papers sold are A

There is no conflict here. It is possible that say 50% (p%) of the papers sold were A and that accounted for 80% (r%) of the revenue (because A is more expensive).

Now check out the solutions here:
http://gmatclub.com/forum/last-sunday-a ... 01739.html


Hi

I have just watch the video and find it pretty impressive, VeritasPrepKarishma would you please provide such a link containing all of OG Solutions in Videos

Thanks
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Re: Last Sunday a certain store sold copies of Newspaper A for  [#permalink]

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New post 10 Aug 2018, 13:56
dassamik89 wrote:
Bunuel Can you please check if my approach is correct:

Assumption: I have assumed P= 50% and the total copies sold as 200.


Therefore Revenue from A= 1*100 =100 and B=1.25*100=125.
Total revenue= 225

Hence r= (100/225)* 100 =400/9.

If we plug in P=50 in all the options only D gives the answer.


First, I realize this is a pretty late reply, so my apologies for that. The good news is that your approach was correct, dassamik89!

I appreciate the lively discussion about algebra vs. number picking on this thread. You all have demonstrated that it can be done either way!

I'm writing to weigh in with my own GMAT Timing Tip on this question. My advice is: Unless you have seen a relatively fast way to do the algebra, I recommend number picking on a question like this where the algebra looks so ugly. So, here is my GMAT Timing Tip (the link has a growing list of questions that you can use to practice applying this tip):

Pick smart numbers to plug into variables in answer choices: While you are ultimately picking a value for p, notice that you are really picking values for A and B that will lead to a nice value for p. Since B is multiplied by 5/4, 4 is a good, easy choice for B. Choices for A that lead to nice values of p are A=1 (p=20) and A=4 (p=50); p=20 is easier to plug into the answer choices, so let’s go with A=1. This means that r=100/6, so we plug in for p and see which answer choice gives us 100/6 for r. Once you have plugged the values into the answer choices, eliminate the answer choices that don't have a multiple of 3 in the denominator (B, C, E), and see that A is not equal to 100/6, but D is.

Please let me know if you have any questions about my timing tip, or if you want me to post a video solution!
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Re: Last Sunday a certain store sold copies of Newspaper A for  [#permalink]

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New post 28 Oct 2018, 14:35
WTF is this guy going here with 'simplify'?

Then:
r=aa+1.25b∗100r=aa+1.25b∗100 and p=aa+b∗100p=aa+b∗100 --> b=ap∗100−a=a(100−p)pb=ap∗100−a=a(100−p)p --> r=aa+1.25∗a(100−p)p∗100r=aa+1.25∗a(100−p)p∗100 --> reduce by aa and simplify --> r=100pp+125−1.25p=100p125−0.25pr=100pp+125−1.25p=100p125−0.25p --> multiply by 4/4 --> r=100p125−0.25p=400p500−pr=100p125−0.25p=400p500−p.

Answer: D.
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Re: Last Sunday a certain store sold copies of Newspaper A for &nbs [#permalink] 28 Oct 2018, 14:35

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