GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 24 Aug 2019, 00:37

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Let P be the product of any three consecutive positive odd integers. T

Author Message
TAGS:

### Hide Tags

Senior Manager
Status: Manager
Joined: 02 Nov 2018
Posts: 283
Let P be the product of any three consecutive positive odd integers. T  [#permalink]

### Show Tags

18 Jul 2019, 08:41
00:00

Difficulty:

75% (hard)

Question Stats:

20% (01:41) correct 80% (01:35) wrong based on 30 sessions

### HideShow timer Statistics

Let P be the product of any three consecutive positive odd integers. The largest integer dividing all such P is:

(A) 15

(B) 6

(C) 5

(D) 3

(E) 1

_________________
Give a kudos if u find my post helpful. kudos motivates active discussions

Intern
Joined: 15 Jul 2018
Posts: 39
Re: Let P be the product of any three consecutive positive odd integers. T  [#permalink]

### Show Tags

18 Jul 2019, 08:53

Since for example 17*19*21 is divisible by 3 and not by 15

Posted from my mobile device
Intern
Joined: 27 Mar 2018
Posts: 1
Re: Let P be the product of any three consecutive positive odd integers. T  [#permalink]

### Show Tags

18 Jul 2019, 21:15
Pick up a case like 9x11x13.
They are all-consecutive positive integers. And it is not divisible by 15. Thus, largest divisible option: 3
And: D
Intern
Joined: 14 Jan 2019
Posts: 3
Re: Let P be the product of any three consecutive positive odd integers. T  [#permalink]

### Show Tags

21 Aug 2019, 00:12
VP
Joined: 03 Jun 2019
Posts: 1058
Location: India
Re: Let P be the product of any three consecutive positive odd integers. T  [#permalink]

### Show Tags

21 Aug 2019, 01:17
Let P be the product of any three consecutive positive odd integers. The largest integer dividing all such P is:

(A) 15

(B) 6

(C) 5

(D) 3

(E) 1

Given: P is the product of any three consecutive positive odd integers.

Asked: The largest integer dividing all such P is:

Let the 3 consecutive odd integers be a-2, a & a+2 where a is odd

P is the product of any three consecutive positive odd integers = (a-2) * a * (a+2)
One of the 3 numbers will be divisible by 3 since
If a=3k => a is divisible by 3 => p is divisible by 3
If a=3k+1 => a+2 is divisible by 3 => p is divisible by 3
If a=3k+2 => a-2 is divisible by 3 => p is divisible by 3
=> E is OUT

Since all numbers are odd => p is NOT divisible by 2 => B is OUT

Let us consider a case e.g. 7,9,11 non of the numbers is divisible by 5. => A & C are OUT

IMO D
_________________
"Success is not final; failure is not fatal: It is the courage to continue that counts."

Please provide kudos if you like my post. Kudos encourage active discussions.

My GMAT Resources: -

Efficient Learning

Tele: +91-11-40396815
Mobile : +91-9910661622
E-mail : kinshook.chaturvedi@gmail.com
Re: Let P be the product of any three consecutive positive odd integers. T   [#permalink] 21 Aug 2019, 01:17
Display posts from previous: Sort by