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Re: List K consists of 12 consecutive integers. If -4 is the [#permalink]

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25 Feb 2013, 21:23

nave81 wrote:

List K consists of 12 consecutive integers. If -4 is the least integer in list K, what is the range of the positive integers in list K?

A. 5 B. 6 C. 7 D. 11 E. 12

Solution:

Set K = ( -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7) Range is defined as the highest value of f(x) and the lowest value of f(x). Over here the range will be 7 - (-4) = 11.

Try making a graph of the set K and see what is the difference between the maximum value and the minimum value.
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Bunnel , I didn't understand when the largest positive integer in the list is 7 , how did the range become 7-1 = 6 , shouldn't it be 7

Pushpinder wrote:

Solution:

Set K = ( -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7) Range is defined as the highest value of f(x) and the lowest value of f(x). Over here the range will be 7 - (-4) = 11.

Try making a graph of the set K and see what is the difference between the maximum value and the minimum value.

The set is {-4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7}. The question asks to find the range of the POSITIVE integers in the list.

The range of the POSITIVE integers in the list is {largest} - {smallest} = 7 - 1 = 6.

Re: List K consists of 12 consecutive integers. If -4 is the [#permalink]

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04 Dec 2016, 14:00

so if it asks you for the positive and negative range then it would be 11 right? 7- (-4)= 11? or do you get two answers one for positive and one for negative?

so if it asks you for the positive and negative range then it would be 11 right? 7- (-4)= 11? or do you get two answers one for positive and one for negative?

The set is {-4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7}.

The range of the POSITIVE integers in the list is {largest} - {smallest} = 7 - 1 = 6. The range of the NEGATIVE integers in the list is {largest} - {smallest} = -1 - (-4) = 3.

The range of the whole set is {largest} - {smallest} = 7 - (-4) = 11.
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