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List P contains m numbers; list Q contains n numbers. If th
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12 Jul 2014, 18:19
Question Stats:
53% (01:53) correct 47% (01:51) wrong based on 226 sessions
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List P contains m numbers; list Q contains n numbers. If the two lists are combined to produce list R, containing m + n numbers, is the median of list R greater than the median of list P ? (1) The smallest number in list Q is greater than the largest number in list P. (2) m = n Need some help; see spoiler below. I got this questions wrong since it was not defined that the any of the numbers are positive, i.e. if the set of n number are negative, then m+n < m, therefore the median of list R is less than the median of list P. However, it if is positive, then median of list R is greater than the median of list P.
Is the word number stating that it is the set of natural numbers?
I picked E Source MGMAT CAT.
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List P contains m numbers; list Q contains n numbers. If th
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Updated on: 13 Jul 2014, 07:38
wunsun wrote: List P contains m numbers; list Q contains n numbers. If the two lists are combined to produce list R, containing m + n numbers, is the median of list R greater than the median of list P ? (1) The smallest number in list Q is greater than the largest number in list P. (2) m = n Need some help; see spoiler below. I got this questions wrong since it was not defined that the any of the numbers are positive, i.e. if the set of n number are negative, then m+n < m, therefore the median of list R is less than the median of list P. However, it if is positive, then median of list R is greater than the median of list P.
Is the word number stating that it is the set of natural numbers?
I picked E Source MGMAT CAT. First, median is the middle number of the set of numbers. Now, statement (1) says that the smallest number of Q is greater than the largest of P. There are three possibilities here: (i)  if m>n then the median will come from the list P as all the n numbers will be greater than the median. It seems that the median would be greater than the median of P but there is the trick (which got me too). What if P consist of all equal numbers? then the median is equal to the median of P. (ii) if m>n then the median will come from the list Q and would be greater than the median of P. (iii)  if m = n then the median will be the average of P's largest number and Q's smallest number. Which would be greater than the median of P (even if P has all equal numbers). So from statement (1) we can get median equal to P or greater than P. Insuff.statement (2) tells us m=n. doesn't tell us what numbers P and Q holds. Insuff.Combining the two: m=n is third scenario discussed in statement (1). i.e. we know that the average of P's largest number and Q's smallest number. Which is greater than the median of P. Suff.Pressing +1 costs nothing
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Originally posted by sameer_kalra on 13 Jul 2014, 06:41.
Last edited by sameer_kalra on 13 Jul 2014, 07:38, edited 3 times in total.




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Re: List P contains m numbers; list Q contains n numbers. If th
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13 Jul 2014, 00:26
I got 1 example for C...
1 and 2 are both insufficient on its own.
4>3 (as per point 1) lets assume m=n=3 P(1,2,3) and Q(4,5,6)
Then median of R (1,2,3,4,5,6) = 3.5 > median of P which is 2. Now expanding that to a larger subset, if smallest digit of Q is always > largest digit of P
This means First digit of Q is > Last digit of P (arrange in ascending order for getting your median). I think it holds true, with random numbers...
Hope this helps.
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List P contains m numbers; list Q contains n numbers. If th
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13 Jul 2014, 06:31
Bunuel,please help.



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List P contains m numbers; list Q contains n numbers. If th
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13 Jul 2014, 07:26
Quote: statement (2) tells us m>n. doesn't tell us what numbers P and Q holds. Insuff. statement 2 is m=n. Great catch on the numbers being equal.



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Re: List P contains m numbers; list Q contains n numbers. If th
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13 Jul 2014, 07:36
peacewarriors wrote: Quote: statement (2) tells us m>n. doesn't tell us what numbers P and Q holds. Insuff. statement 2 is m=n. Great catch on the numbers being equal. sorry for missing that. post edited. Hope i helped.
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Re: List P contains m numbers; list Q contains n numbers. If th
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17 Aug 2015, 09:13
Quote: List P contains m numbers; list Q contains n numbers. If the two lists are combined to produce list R, containing m + n numbers, is the median of list R greater than the median of list P ?
(1) The smallest number in list Q is greater than the largest number in list P.
(2) m = n Need some help. How do we know whether to take positive number or negative number or odd or even. Because if m/n is odd/even, then the median can change between integer and non integer.



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Re: List P contains m numbers; list Q contains n numbers. If th
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20 Sep 2015, 05:23
sameer_kalra wrote: First, median is the middle number of the set of numbers.
Now, statement (1) says that the smallest number of Q is greater than the largest of P.
There are three possibilities here: (i)  if m>n then the median will come from the list P as all the n numbers will be greater than the median. It seems that the median would be greater than the median of P but there is the trick (which got me too). What if P consist of all equal numbers? then the median is equal to the median of P.
(ii) if m>n then the median will come from the list Q and would be greater than the median of P.
For (i)  if m>n, from Sameer's post we can also have P =(1,2,3,4,5,6,7) and Q = (9,10)..even in this case the median is from P. In this case the elements of P are all not the same. (ii) from from Sameer's post must be m < n... in case Q has more number of terms such that "The smallest number in list Q is greater than the largest number in list P", then the median will be from Q.



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Re: List P contains m numbers; list Q contains n numbers. If th
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20 Sep 2015, 05:31
Mechmeera wrote: Quote: List P contains m numbers; list Q contains n numbers. If the two lists are combined to produce list R, containing m + n numbers, is the median of list R greater than the median of list P ?
(1) The smallest number in list Q is greater than the largest number in list P.
(2) m = n Need some help. How do we know whether to take positive number or negative number or odd or even. Because if m/n is odd/even, then the median can change between integer and non integer. m and n can be anything  odd/even... if m is odd, but the terms are 0.5, 0.5, 0.5 > the median would be a noninteger if m is odd, but the terms are 1, 1, 1 > the median would be an integer if m is even and the terms are 1,2,2,4.. the median can still be an integer. if m is even and the terms are 1,2,3,4.. the median will be a noninteger. the value of median would depend on the value of elements and not the number of elements



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Re: List P contains m numbers; list Q contains n numbers. If th
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20 Sep 2015, 05:37
we have a takeaway from this question...
we can use the options presented in the DS question to our advantage. In this question, statement 2 says number of terms are same.
We should take this as a hint while examining statement 1. We have to ask ourselves whether we have considered the scenario where m = n, m > n etc
I did not follow this...got the wrong answer!



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Re: List P contains m numbers; list Q contains n numbers. If th
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09 Jan 2016, 08:26
Success2015 wrote: we have a takeaway from this question...
we can use the options presented in the DS question to our advantage. In this question, statement 2 says number of terms are same.
We should take this as a hint while examining statement 1. We have to ask ourselves whether we have considered the scenario where m = n, m > n etc
I did not follow this...got the wrong answer! Experts posts will be appreciated in this



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Re: List P contains m numbers; list Q contains n numbers. If th
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09 Jan 2016, 09:13
Nez wrote: ]
Experts posts will be appreciated in this This is a great question to understand how you can play around with the information given in the DS question. You are given 2 sets with m and n elements each. nowhere it is mentioned whether m=n or whether you can have same elements in any given set. You can thus use these things to your advantage. Additionally, statement 2 should give you that bit of clue. The question wants to know whether the median of R is > median of P. Start by analyzing the 2 statements. Per statement 1, P={1}, Q = {2,3}, R={1,2,3} will give you a "yes" for the question asked but with P={1,1,1}, Q = {2,3}, R={1,1,1,2,3} will give you a "no" for the question asked. This statement is thus not sufficient. Per statement 2, m=n, again P={1,1}, Q = {2,3}, R={1,1,2,3} will give you a "yes" for the question asked but with P={10,10}, Q = {2,3}, R={2,3,10,10} will give you a "no" for the question asked. This statement is thus not sufficient. Combining, you get that the min element of Q > max. element of P and m=n, giving you in all possibilities that the median of R > median of P. C is thus the correct answer. Hope this helps.



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