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# LOWEST positive interger divisible

Author Message
Manager
Status: GMAT Preperation
Joined: 04 Feb 2010
Posts: 101

Kudos [?]: 190 [0], given: 15

Concentration: Social Entrepreneurship, Social Entrepreneurship
GPA: 3
WE: Consulting (Insurance)

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28 Oct 2010, 01:08
00:00

Difficulty:

35% (medium)

Question Stats:

78% (00:22) correct 22% (00:10) wrong based on 9 sessions

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what is the lowest positive integer that is divisible by easch of the integers 1 through 7 inclusive?
420
840
1260
2520
5020

looking forward to the shortest possible way to get the answer
[Reveal] Spoiler: OA

Kudos [?]: 190 [0], given: 15

Manager
Joined: 08 Sep 2010
Posts: 223

Kudos [?]: 326 [0], given: 21

Location: India
WE 1: 6 Year, Telecom(GSM)
Re: LOWEST positive interger divisible [#permalink]

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28 Oct 2010, 01:27
vanidhar wrote:
what is the lowest positive integer that is divisible by easch of the integers 1 through 7 inclusive?
420
840
1260
2520
5020

looking forward to the shortest possible way to get the answer

We have to find out the LCM of 1,2,3,2^2,5,2*3,7

Hence LCM = 1*3*2^2*5*7= 420
_________________

Consider KUDOS if You find it good

Kudos [?]: 326 [0], given: 21

Intern
Joined: 26 Mar 2010
Posts: 47

Kudos [?]: 10 [0], given: 5

Re: LOWEST positive interger divisible [#permalink]

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28 Oct 2010, 07:35
2, 3, 5 and 7 are all prime, and multiplying them gives 210.

4 is 2*2, so multiplying 210 by 2 gives 420.

6 is 2*3, but since both 2 and 3 are already prime and included as factors of 420, no need to multiply them again. That leaves 420 as the LCM of 7!.

Kudos [?]: 10 [0], given: 5

Re: LOWEST positive interger divisible   [#permalink] 28 Oct 2010, 07:35
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