GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 21 Nov 2018, 06:09

# LBS is Calling R1 Admits - Join Chat Room to Catch the Latest Action

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

## Events & Promotions

###### Events & Promotions in November
PrevNext
SuMoTuWeThFrSa
28293031123
45678910
11121314151617
18192021222324
2526272829301
Open Detailed Calendar
• ### All GMAT Club Tests are Free and open on November 22nd in celebration of Thanksgiving Day!

November 22, 2018

November 22, 2018

10:00 PM PST

11:00 PM PST

Mark your calendars - All GMAT Club Tests are free and open November 22nd to celebrate Thanksgiving Day! Access will be available from 0:01 AM to 11:59 PM, Pacific Time (USA)
• ### Key Strategies to Master GMAT SC

November 24, 2018

November 24, 2018

07:00 AM PST

09:00 AM PST

Attend this webinar to learn how to leverage Meaning and Logic to solve the most challenging Sentence Correction Questions.

# Luis is taller than Rei. Kiko is taller than Marcus. Theref

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
TAGS:

### Hide Tags

Board of Directors
Joined: 01 Sep 2010
Posts: 3302
Luis is taller than Rei. Kiko is taller than Marcus. Theref  [#permalink]

### Show Tags

Updated on: 10 Oct 2017, 11:25
5
00:00

Difficulty:

25% (medium)

Question Stats:

75% (01:28) correct 25% (01:21) wrong based on 258 sessions

### HideShow timer Statistics

Luis is taller than Rei. Kiko is taller than Marcus. Therefore, Kiko is taller than Rei.

The conclusion drawn above is not supported by the argument; however, the addition of one additional piece of information would make the conclusion logically sound. All of the following could be that additional piece of information EXCEPT:

(A) Kiko is taller than Luis.
(B) Luis is taller than Marcus.
(C) Luis and Marcus are the same height.
(D) Marcus and Rei are the same height.
(E) Marcus is taller than Rei.

_________________

Originally posted by carcass on 15 Dec 2013, 03:59.
Last edited by mvictor on 10 Oct 2017, 11:25, edited 1 time in total.
Current Student
Joined: 04 Oct 2013
Posts: 75
Location: Brazil
GMAT 1: 660 Q45 V35
GMAT 2: 710 Q49 V38
Re: Luis is taller than Rei. Kiko is taller than Marcus. Theref  [#permalink]

### Show Tags

15 Dec 2013, 10:15
B is the way to go. Picking numbers and a bar-chart help to solve this question. Let's say that Luis is 100, and Marcus is 50. Rei can still be 90, and Kiko can be 80. Conditions satisfy but it is not true.

Cheers,

carcass wrote:
Luis is taller than Rei. Kiko is taller than Marcus. Therefore, Kiko is taller than Rei.

The conclusion drawn above is not supported by the argument; however, the addition of one additional piece of information would make the conclusion logically sound. All of the following could be that additional piece of information EXCEPT:

(A) Kiko is taller than Luis.
(B) Luis is taller than Marcus.
(C) Luis and Marcus are the same height.
(D) Marcus and Rei are the same height.
(E) Marcus is taller than Rei.
Intern
Joined: 22 Jul 2009
Posts: 9
Re: Luis is taller than Rei. Kiko is taller than Marcus. Theref  [#permalink]

### Show Tags

16 Dec 2013, 10:46
The answer is B.

1. K>L>M>R
2. L>R>K>M in second case K is less than R..

Thanks
Rahul
Manager
Joined: 23 Jan 2013
Posts: 145
Concentration: Technology, Other
Schools: Berkeley Haas
GMAT Date: 01-14-2015
WE: Information Technology (Computer Software)
Re: Luis is taller than Rei. Kiko is taller than Marcus. Theref  [#permalink]

### Show Tags

01 Apr 2014, 18:57
Consider with the given senario two possibilities exists
1) K > M > L > R

2) K > L > R > M

Now with knowing

a ) K > L with this information we still cannot fix the above possibilities .
b) L > M possibility 2 occurs
c) L = M possibility 2 occurs
d) M = R possibility 1 occurs
e) M > R possibility 1 occurs

Hence i feel a is the answer can any one comment on this '>' here means greater in terms of height !!
Intern
Joined: 11 Dec 2012
Posts: 29
Re: Luis is taller than Rei. Kiko is taller than Marcus. Theref  [#permalink]

### Show Tags

20 Apr 2015, 05:41
Luis is taller than Rei. Kiko is taller than Marcus. Therefore, Kiko is taller than Rei.

The conclusion drawn above is not supported by the argument; however, the addition of one additional piece of information would make the conclusion logically sound. All of the following could be that additional piece of information EXCEPT:

(A) Kiko is taller than Luis.
(B) Luis is taller than Marcus.
(C) Luis and Marcus are the same height.
(D) Marcus and Rei are the same height.
(E) Marcus is taller than Rei.

Looks like E
in brief: L>R; K>M; Hence K>R. Where is the linking point? If K>M in order K to be '>' than R, M must be '>' than R.
Manager
Joined: 08 Oct 2016
Posts: 204
Location: United States
Concentration: General Management, Finance
GPA: 2.9
WE: Engineering (Telecommunications)
Re: Luis is taller than Rei. Kiko is taller than Marcus. Theref  [#permalink]

### Show Tags

11 Jan 2018, 20:59
1
Although it took time that is 1 minute 47 second still attempted right
My approach
luis>rei
kiko>marcus
kiko>rei
1.. can be possible
2..hold on-- It the left over choice
3...yes possibe refer option A
4.. Yes possible since both are shorter than luis and Kiko
5..Possible since still atleast shorter than Kiko
I am not good at explaining things by the way just learning
_________________

Got Q42,V17
Target#01 Q45,V20--April End

Re: Luis is taller than Rei. Kiko is taller than Marcus. Theref &nbs [#permalink] 11 Jan 2018, 20:59
Display posts from previous: Sort by

# Luis is taller than Rei. Kiko is taller than Marcus. Theref

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.