It is currently 23 Jun 2017, 17:51

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# M=O+P+Q, where O, P, and Q are consecutive positive integer;

 post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
Manager
Joined: 03 Jul 2006
Posts: 175
M=O+P+Q, where O, P, and Q are consecutive positive integer; [#permalink]

### Show Tags

12 Sep 2006, 20:09
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 1 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

M=O+P+Q, where O, P, and Q are consecutive positive integer; M=R*S*T, where R, S and T are positive consecutive integers. What is the remainder when M is divided by 5?
1). When O is divided by 5, the remainder is 1
2). When R is divided by 5, the remainder is 1

Q: If O, P, and Q are consecutive positive integer, is it safe to assume O < P < Q ?
VP
Joined: 25 Jun 2006
Posts: 1166

### Show Tags

12 Sep 2006, 20:14

it does not matter whether they are consecutively increasing or not.
CEO
Joined: 20 Nov 2005
Posts: 2894
Schools: Completed at SAID BUSINESS SCHOOL, OXFORD - Class of 2008

### Show Tags

12 Sep 2006, 20:58
tennis_ball wrote:

it does not matter whether they are consecutively increasing or not.

I think it matters.
Lets say if O = 6 , P = 5 and Q = 7 then remainder is 3
if O = 6 P = 7 and Q = 8 then remainder is 1.

But I think it is safe to assume O<P<Q.

St1:
Let O = x then
M = x+x+1 + x+2 = 3x+3
x/5 has a remainder of 5. 3x will have a remainder of 3 and 3x+3 will have a remainder of 1: SUFF

St2: Let R = x
Then M = x(x+1)(x+2) = x^3 + 3x^2 + 2x
x/5 has a remainder of 1. This means last digit of x is either 1 or 6.
So last digit of x^3 will be either 6 or 1. i.e Remainder = 1
Last digit of x^2 will be either 6 or 1. Last digit of 3x^2 will be either 8 or 3. i.e remainder = 3
Last digit of 2x will be 2 - i.e remainder = 2

Total remainder = 1+3+2 = 6
Hence final remainder will be 6-5 = 1: SUFF

Hence answer is D
_________________

SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008

Director
Joined: 13 Nov 2003
Posts: 789
Location: BULGARIA

### Show Tags

13 Sep 2006, 02:09
Think it is E)
O-5,Q-6,R-7 them M=18 rem-3
O-6,Q-5,R-4 then M=15 rem is 0
A Is NOT suff

B)
Numbers may be 5,6,7 where the product is divisible by 5 without reminder or 6,7,8 where there will be a remainder
B is NOT suff

E should be it

So it is not safe to assume anything, IMO
Intern
Joined: 04 May 2006
Posts: 40

### Show Tags

13 Sep 2006, 07:21
Does anyone know for sure whether we can assume an increasing order?
VP
Joined: 25 Jun 2006
Posts: 1166

### Show Tags

13 Sep 2006, 08:16
WHAT is the OA? then we know whether we can assume.
GMAT Instructor
Joined: 04 Jul 2006
Posts: 1262

### Show Tags

13 Sep 2006, 14:04
tennis_ball wrote:
WHAT is the OA? then we know whether we can assume.

We can assume that they are ascending order- that's what consecutive means!
SVP
Joined: 05 Jul 2006
Posts: 1747

### Show Tags

15 Sep 2006, 01:27
kevin am lost here... as the numbers are consecutive we still can never know the order

what am i missing here

Plz Help
VP
Joined: 02 Jun 2006
Posts: 1260

### Show Tags

15 Sep 2006, 06:56
This can be E or D depending upon whether we consider O < P < Q.

PS,
On the GMAT can we assume O < P < Q? Or is it usually specified?

Thanks/
Manager
Joined: 01 Jun 2006
Posts: 139
Re: DS:consecutive integers [#permalink]

### Show Tags

15 Sep 2006, 08:41
I found a solution here
C it is
(1) alone we have O divided by 5 remainder is 1 so O,P,Q divided by 5 must have remainder is one of these sets (0,1,2);(1,2,3);(4,0,1).So M diveded by 5 could have remainder of 3 or 1(1+2+3=6) or 0. This tells us nothing
(2) alone R,S,T divided by 5 must have remainder is one of these sets (0,1,2);(1,2,3);(4,0,1). So M diveded by 5 could have remainder of 2 or 1 or 4 . This also tells nothing
But(1)(2) together we can say that M divided by 5 must have remainder of 1
Senior Manager
Joined: 15 Jul 2006
Posts: 381

### Show Tags

15 Sep 2006, 09:44
I'd say D:

1)reminders (o,p,q) = (1,2,3) 1+2+3=6 6/5 = reminder 1

2)reminders (r,s,t) = (1,2,3) 1*2*3=6 6/5 = reminder 1
Current Student
Joined: 28 Dec 2004
Posts: 3357
Location: New York City
Schools: Wharton'11 HBS'12

### Show Tags

15 Sep 2006, 09:55
I say this E..

M=O+P+Q; M=R*S*T

we are told (o, p, q) (r, s, t) they are consecutive numbers

(1)when o is divided by 5 remainder is 1

so say o is 6, then p=7, q=8...remainder will be 1

however if o=6, p=5, q=4; then remainder will be 0....

Insuff

(2) same thing if R=6, s=7, t=8 remainder is given..however if r=6, s=5 and t=4..then remainder is 0...

together its insuff too...

E it is...

if however it is an ascending order...then its a D..
Director
Joined: 28 Dec 2005
Posts: 752

### Show Tags

15 Sep 2006, 11:06
D for me

From stem:

m = x+(x+1)+(x+2) = 3x+3 so m is divisible by 3

also

m = y.(y+1).(y+2)...so m is divisible by 6 ok...

From 1:
O=5k+1
So O+P+Q=15k+6 which will leave a remainder of 1

Suff

From 2:
R=5k+1
So RST=(5k+1)(5k+2)(5k+3) = 125k^3 + 150k^2 +55k + 6...again remainder is alway 1...SUFF
15 Sep 2006, 11:06
Display posts from previous: Sort by

# M=O+P+Q, where O, P, and Q are consecutive positive integer;

 post reply Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group and phpBB SEO Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.