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• All GMAT Club Tests are Free and open on November 22nd in celebration of Thanksgiving Day!

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M00-03

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Joined: 02 Sep 2009
Posts: 50730

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08 Oct 2017, 07:37
mackhandelwal wrote:
Hi,
If I solve the question by using method :
2 apprentices-2*3/4*5=7.5 hours
2 trainees-2*(1/5)*5=2 hours
1 worker-5 hours

so,(1/7.5 +1/2+1/5) * x=1
so comes out to be 1 hr 12 min.

If 1 apprentices can work $$\frac{3}{4}$$ as fast as a qualified worker and if a qualified worker needs 5 hours, then 1 apprentice will need 4/3 as much time, so 20/3 hours, thus 2 apprentices, will need half that time, 20/6 hours.

If 1 trainee can work $$\frac{1}{5}$$ as fast as a qualified worker and if a qualified worker needs 5 hours, then 1 trainee will need 5 times as much time, so 25 hours, thus 2 trainees, will need half that time, 25/2 hours.

(1/5 + 6/20 + 2/25)*x = 1

x = 50/29.
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Joined: 02 Sep 2009
Posts: 50730

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08 Oct 2017, 07:41
Bunuel wrote:
mackhandelwal wrote:
Hi,
If I solve the question by using method :
2 apprentices-2*3/4*5=7.5 hours
2 trainees-2*(1/5)*5=2 hours
1 worker-5 hours

so,(1/7.5 +1/2+1/5) * x=1
so comes out to be 1 hr 12 min.

If 1 apprentices can work $$\frac{3}{4}$$ as fast as a qualified worker and if a qualified worker needs 5 hours, then 1 apprentice will need 4/3 as much time, so 20/3 hours, thus 2 apprentices, will need half that time, 20/6 hours.

If 1 trainee can work $$\frac{1}{5}$$ as fast as a qualified worker and if a qualified worker needs 5 hours, then 1 trainee will need 5 times as much time, so 25 hours, thus 2 trainees, will need half that time, 25/2 hours.

(1/5 + 6/20 + 2/25)*x = 1

x = 50/29.

17. Work/Rate Problems

For more check:
ALL YOU NEED FOR QUANT ! ! !

Hope it helps.
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Joined: 08 Oct 2017
Posts: 1
GMAT 1: 640 Q49 V30
GPA: 4

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08 Apr 2018, 00:56
Bunuel

I solved the question using the below approach
Let A be the qualified worker, B be the apprentice and C be the trainees
A does 20% of the work in 1 hour as he completes the work in 5hours.
B does 15% of work in 1 hour. So 2B does 30% of work in 1 hour
C does 24%of work in 1 hour. So 2C does 48% of work in 1 hour.

Therefore in 1 hour they all combined can complete 20 + 30 + 48 = 98% of the work.

Using this approach the I answer that I would get is nowhere close to the answer choices.

Re: M00-03 &nbs [#permalink] 08 Apr 2018, 00:56

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