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M01-17

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Re: M01-17  [#permalink]

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New post 05 Jul 2018, 03:21
1
Only thing I would like to highlight once again for this problem is that have a set of numbers to test on each and every DS question. For statement (1) it was very important to test for zero. It does not strike naturally for this statement that m could be zero.

Hence develop a habit to test numbers systematically. Use a standard set of numbers during your practice sessions so that this becomes a habit. After reading the constraints mentioned in question stem and the 2 statements, you could test for (assuming no constraints) -2,\(\frac{-3}{2}\),-1,\(\frac{-1}{2}\),0,\(\frac{1}{2}\),1,\(\frac{3}{2}\) and 2.

Please read my overall understanding on DS questions and few useful tips:-

https://gmatclub.com/forum/data-suffici ... l#p2073589
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Re: M01-17  [#permalink]

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New post 20 Jul 2018, 06:07
Hi,

|x| = -x if x<0
|x| = x if x>0

In this scenario |-m| = -(-m) = m if -m<0, hence m>0
|-m| = -m if -m>0, Hence m<0

According to statement 1, |-m| = -m, hence -m>0, hence m<0, Hence statement 1 is sufficient.
Please let me know why is thought process incorrect?
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Re: M01-17  [#permalink]

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New post 20 Jul 2018, 09:35
Fervids77 wrote:
Hi,

|x| = -x if x<0
|x| = x if x>0

In this scenario |-m| = -(-m) = m if -m<0, hence m>0
|-m| = -m if -m>0, Hence m<0

According to statement 1, |-m| = -m, hence -m>0, hence m<0, Hence statement 1 is sufficient.
Please let me know why is thought process incorrect?


I think this is explained in the solution as well as in the discussion. Please re-read.
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Re: M01-17  [#permalink]

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New post 20 Jul 2018, 09:45
Hi,

I re read the solution, but unable to understand the flaw in my logic
Please advise
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Re: M01-17  [#permalink]

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New post 20 Jul 2018, 09:54
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Re: M01-17  [#permalink]

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New post 20 Jul 2018, 10:03
Hi,

Thanks for the response. It is clear now
So if the question was is m>=0 then statement would be sufficient
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Re: M01-17 &nbs [#permalink] 20 Jul 2018, 10:03

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