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Re: M01-26 [#permalink]
I think this is a high-quality question and I agree with explanation.
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Re: M01-26 [#permalink]
Bunuel Bunuel

How is an integer a multiple of itself?
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Re: M01-26 [#permalink]
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Ruchi007 wrote:
Bunuel Bunuel

How is an integer a multiple of itself?


When we say "integer 'a' is a multiple of integer 'b'," it means 'a' can be written as 'x*b', where 'x' is some integer. And since any integer 'a' can be expressed as '1*a', it's correct to say every integer is a multiple of itself.

For example, 5 is a multiple of 5, 11 is a multiple of 11, 36 is a multiple of 36, and so on.

The statement "integer 'a' is a multiple of integer 'b'" implies that 'a = x*b', where 'x' is some integer (the multiplier). Since we can express any integer 'a' as 'a = 1*a', it follows that every integer is indeed a multiple of itself.

As examples, 5 is a multiple of 5, 11 is a multiple of 11, 36 is a multiple of 36, and so on.

Hope it's clear.
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Re: M01-26 [#permalink]
I think this is a high-quality question and I agree with explanation.
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Re: M01-26 [#permalink]
Isn't the first condition complete in itself?
For x to be a multiple of prime number, x has to be a prime number, right?

Posted from my mobile device
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Re: M01-26 [#permalink]
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deorapalak wrote:
Isn't the first condition complete in itself?
For x to be a multiple of prime number, x has to be a prime number, right?

Posted from my mobile device


Have you read the solution?
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Re: M01-26 [#permalink]
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