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m01-qs 18

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Manager
Manager
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Joined: 05 Mar 2011
Posts: 145

Kudos [?]: 68 [0], given: 3

m01-qs 18 [#permalink]

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New post 25 Dec 2011, 13:22
How many of the three-digit numbers are divisible by 7?

105
106
127
128
142


Approach One: Divide all of the three-digit numbers (Don't forget to add 1 to get the number of all the 3-digit numbers) by 7, which is 128.57, and then round it off to 128.

Approach Two: Find the first and the last multiples of 7 WITHIN the range (which is between 105 and 994). Find the positive difference, divide by 7, and add 1:

994-105/7+1=128
I hv a qs about this approach 1 -I followed the mgamt approach which took me a lot longer to solve which is the 2nd approach mentioned in this prob

but when I tested approach 1 for anther prob of the similar type i got the ans wrong
how many nos betw 94 and 302 are / by 3
302-94+1=209
209/3=69.66777 which rounded of is 70 not 69

if u use mgmat approach
the ans is 69


M i missing something?
300-96/3+1=69

Kudos [?]: 68 [0], given: 3

Senior Manager
Senior Manager
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Joined: 18 Sep 2009
Posts: 352

Kudos [?]: 601 [0], given: 2

Re: m01-qs 18 [#permalink]

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New post 26 Dec 2011, 09:15
how many nos betw 94 and 302 are / by 3
302-94+1=209
209/3=69.66777 which rounded of is 70 not 69

the value is 69.66. the value after decimal is more than 5 so we need to round up to 70.
If the value is 69.2 (lessthan 5 like 1,2,3,4 it must be 69 )
If the value is 69.66(more than 5 like 5,6,7,8,9 it must be 70)

Kudos [?]: 601 [0], given: 2

Re: m01-qs 18   [#permalink] 26 Dec 2011, 09:15
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m01-qs 18

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