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m02#29

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Joined: 06 Feb 2012
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m02#29 [#permalink]

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12 Feb 2012, 19:33
Is x=x^2?

(1) x does not equal 0.
(2) x > 1

Okay, so I agree with x > 1 being sufficient, however, I think the answer is D, both statements alone are sufficient.

For statement 1: If x does not equal zero, then we can divide by x, hence x =1 an we know x = x^2. Thoughts?

Last edited by Bunuel on 13 Feb 2012, 05:58, edited 1 time in total.
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Re: m02#29 [#permalink]

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13 Feb 2012, 06:10
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Is x=x^2?

x=x^2 holds true for x=0 or x=1 (x=x^2 --> x^2-x=0 --> x(x-1)=0 --> x=0 or x=1). So basically the question asks whether x is one of these two values.

(1) x does not equal 0. So one value is out but x can be 1 as well as any other number (except 0). Not sufficient.
(2) x > 1 --> x neither 0 nor 1, so the answer to the question is NO. Sufficient.

Answer: B.

robertian23 wrote:
Okay, so I agree with x > 1 being sufficient, however, I think the answer is D, both statements alone are sufficient.

For statement 1: If x does not equal zero, then we can divide by x, hence x =1 an we know x = x^2. Thoughts?

Question asks: "is x=x^2?", since for (1) x does not equal 0 then, yes, you can divide by it and the question becomes: "is x=1?" (We are asked to determine whether x=x^2 is true and you've taken this as given statement).

Hope it's clear.
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Re: m02#29 [#permalink]

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13 Feb 2012, 06:41
Makes sense now. Thanks!

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Re: m02#29   [#permalink] 13 Feb 2012, 06:41
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