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# M03-18

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Intern
Joined: 18 Jan 2018
Posts: 24
Location: India
Concentration: Finance, Marketing
GPA: 3.98

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09 Mar 2019, 05:21
Bunuel in this question, I took x = (x^2) and hence calculated the roots for (x^2)^2-2(x^2)+1 by the formula root(B^2-4ac) which turned out to be 0 and hence, I marked choice B. Am I missing something?
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Joined: 02 Sep 2009
Posts: 53792

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09 Mar 2019, 07:10
aalakshaya wrote:
Bunuel in this question, I took x = (x^2) and hence calculated the roots for (x^2)^2-2(x^2)+1 by the formula root(B^2-4ac) which turned out to be 0 and hence, I marked choice B. Am I missing something?

$$(x^2)^2-2(x^2)+1 =0$$

$$x^2=\frac{2+\sqrt{4-4}}{2}$$ --> $$x^2=1$$ --> $$x=1$$ or $$x = -1$$;

$$x^2=\frac{2-\sqrt{4-4}}{2}$$ --> $$x^2=1$$ --> $$x=1$$ or $$x = -1$$.
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Re: M03-18   [#permalink] 09 Mar 2019, 07:10

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# M03-18

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