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* Statement (1) ALONE is sufficient, but Statement (2) ALONE is not sufficient * Statement (2) ALONE is sufficient, but Statement (1) ALONE is not sufficient * BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient * EACH statement ALONE is sufficient * Statements (1) and (2) TOGETHER are NOT sufficient

has to be C.

1: n = lets say 2 but x could be -1, 0, 0.5, 2. Then in all cases, n^x is not an even. so nsff.. 2: x = 1 or 2 but what is n? nsf.

This question reminds us the importance of fraction, negatives and zero. I lost out on my previous GMAT cuz of this, so now before freezing on the answer for variables in question always remember frazen(fractions, zero and negatives)

Hi, C is the correct option because even if N is even N^x can be odd. Consider for example N = 4 N^0 = 4^0 =1 which is odd If we consider the second statement then we come to know that x can be either 1 or 2. So from 1 and 2 both we can answer the question properly hence the solution for this is C.

How did you get x=1 or X=2 from x2 -3X+2 = 0. Just from trying figures starting from 0 or can the equation be written in a way that makes it solution obvious ?

How did you get x=1 or X=2 from x2 -3X+2 = 0. Just from trying figures starting from 0 or can the equation be written in a way that makes it solution obvious ?

Hi, You need to know the basics of quadratic equation to solve. Try searching for Crammers Rule.

I chose (A) at first as well. We don't know whether X is an integer or not, that made sense for me. So the correct answer is (C) as far as we learn that N is a positive integer.

The answer is the first option. An even number raised to any number is always even. However, for the quadratic equation, x=1,2. And it cannot be certainly be told if N^x is even without knowing the value of N.

Statement 1: Insufficient. x could be 1 or x could be 0. Statement 2: Insufficient. After factoring x = 2 or x = 1. We also do not know anything about N.

Combined 1 + 2. We know that N is even. An even number raised to either 1 or 2 would still be EVEN. Sufficient. C.

N^x will must be even if a) N is even & b) x is non negative & non zero

i) Says N is even but doesn't say abt x ii) Gives x as 1 or , but doesn't say abt N combining both we get N even & x 1 or 2 so N^x must be even.. Hence 'C'