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Re: M03 #01 [#permalink]
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17 Jan 2011, 02:35
Answer will be E. I is insufficient because X = (1,2) U (3,infinity) and II is also not sufficient as X> 1, in this cas X can be 1.5,2,2.5 etc. combining I and II is not sufficient.



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Re: M03 #01 [#permalink]
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24 Jan 2011, 03:55
Hi, I tried to explain the process in this post: m0370436.html#p624356Let me know what exactly is not clear if anything. gmatpapa wrote: nvgroshar wrote: Just sketch the graph of y=(x1)(x2)(x3) and get the answer E. Can anyone explain how to do so? How do we plot graphs to find the signs of the roots?
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Re: M03 #01 [#permalink]
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26 May 2011, 09:45
IEsailor wrote: is x > 3
1.) (x3)(x2)(x1)>0 2.) x > 1 Q: x>3? 1.(x3)(x2)(x1)>0 Roots: 1,2,3 Range: x>3; 1<x<2 Not Sufficient. 2. x>1 Not Sufficient. Combining both; x can be any number between 1 and 2 OR it can be greater than 3. Not Sufficient. Ans: "E" ********************** Explanation of my approach lies here: inequalitiestrick91482.html
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Re: M03 #01 [#permalink]
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26 May 2011, 09:52
IEsailor wrote: Hi Fluke, Can you pls explain in detail the reasoning behind the explanation of the first part.
Thnx Did you see this: inequalitiestrick91482.htmlPlease let me know if you don't understand the approach.
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Re: M03 #01 [#permalink]
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11 Jun 2011, 18:36
1. Not sufficient
(x3)(x2)(x1) >0
x>3 x is greater than 3.
x>1 and x<2 => x is not greater than 3.
2. Not sufficient
x>1
x =2 =>x is not greater than 3 x =4 x is greater than 3.
together,
both the examples in 1 applies here as well. Still not sufficient.
Answer is E.



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Re: M03 #01 [#permalink]
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17 Jan 2012, 07:11
Ans is E. statement 1: x>3,x>2 and x>1 => not sufficient statement 2: x>1 => not sufficient
together also both statement not sufficient. So ans is E



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Re: M03 #01 [#permalink]
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30 Jan 2014, 04:44
Ans is E.
Consider 1st statement; (x3)(x2)(x1)>0 This is true in 4 cases: Case 1: (x3), (x2), (x1) all are > 0, which is possible if x>3 {x3 > 0} Case 2: (x3) > 0 and (x2) and (x1) < 0 which is not possible if x>3 Case 3: (x3) and (x2)< 0 and (x1) > 0 which is possible if 1<x<2 Case 4: (x3) and (x1)< 0 and (x2) > 0 which is not possible if x>2 [since x1 can not be negative for x>2] This gives two possible answers from Case 1 (x>3) & case 3 (1<x<2). Therefore, this statement is NOT SUFFICIENT
Consider 2nd statement; x>1 That does not tell us if x>3 or x<3, x could be 1.5, 2, 2.5 etc...Hence, this is NOT SUFFICIENT
Combining 1st and 2nd statement does not give us exact value of x. Hence, the answer should be E



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Re: M03 #01 [#permalink]
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20 Apr 2014, 06:48
1) Both X=4 and X=1.5 satisfy (X3)(X2)(X1)>0 > insufficient 2) Clearly insufficient Combine 2 stats: still cannot, using the same examples as in 1)
> Choose E







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