GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 16 Oct 2019, 13:06

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# M04-24

Author Message
TAGS:

### Hide Tags

Intern
Joined: 23 Aug 2016
Posts: 10

### Show Tags

14 Jun 2018, 09:28
It is really hard to remember all the rules with the medians in different types of triangles. Is there any simple way?
Intern
Joined: 18 May 2018
Posts: 17
Location: India
Concentration: Marketing, Strategy
Schools: DeGroote'21 (A)
GMAT 1: 730 Q49 V40

### Show Tags

05 Oct 2018, 07:16
I think this is a high-quality question and I agree with the explanation.

A very clever manipulation of the 'triangle inside a semicircle' trope. Bravo!
Intern
Joined: 13 Dec 2014
Posts: 5
Location: India
Schools: NUS '21
GMAT 1: 700 Q48 V39
GPA: 2.4

### Show Tags

06 Oct 2018, 07:44
Does median BD make 90 degree angle at AC?
and is it true in general for right angled triangle.
Senior Manager
Joined: 15 Feb 2018
Posts: 365

### Show Tags

23 Dec 2018, 17:35
Contributors discussing this question on other sites state that it is beyond the scope of the GMAT. I had not come across this concept of triangle median prior to this question. Are there official questions that include it?
Manager
Joined: 06 Aug 2015
Posts: 56
Concentration: General Management, Entrepreneurship
GMAT Date: 10-30-2016
GRE 1: Q160 V135
GPA: 3.34
WE: Programming (Consulting)

### Show Tags

27 May 2019, 08:28
I have followed the following approach to reach to solution. (Using Circumscribed triange properties)

Since, BD is a median in triangle ABC, AD = DC. Now, lets go through the given options
1. By itself is insufficient as we are not told about the sides that are same and its difficult to find out AC.

2. Since AC^2 = AB^2 + BC^2 implies that the Triangle is right angle at B.
Now, using the property of Circumscribed circle.
Draw a circle through the vertices. It implies that AC is the diameter and D is the center of the circle.
Since BD = 12 i.e it is the radius of circle.
Therefore, BD = AD = DC = 12.
=> AC = 2 * BD = 24
Hence Sufficient.

B

Re: M04-24   [#permalink] 27 May 2019, 08:28

Go to page   Previous    1   2   [ 25 posts ]

Display posts from previous: Sort by

# M04-24

Moderators: chetan2u, Bunuel