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# M04 #1

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Director
Joined: 01 Feb 2011
Posts: 726

Kudos [?]: 143 [0], given: 42

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11 Jun 2011, 18:45
lets say the normal speed is v => v= d/t1

where t1 is the time taken to cover distance d.

when speed is
v/1.5 = d/t2

1. Sufficient

v/1.5 = d/t1+15

v = d/t1

solving these two equations t1 can found out.

2. Not sufficient

d = 15

no info on v or there is no way to find out t1.

Kudos [?]: 143 [0], given: 42

Intern
Joined: 10 Jan 2012
Posts: 27

Kudos [?]: 18 [0], given: 22

Concentration: Strategy, Finance
GMAT Date: 10-17-2013
WE: Consulting (Computer Software)

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18 Jan 2012, 23:36
Rate and Work problems are handled like this.

Rate x Time = Distance (Work)

Now in this question below is given:
Time2 = 1.5 Time1 .... (1)And question is asking Time1 =?

Statement1 : Time2 = 15 + Time1 ... (2).
Using both we get 1.5Time1 = 15 + Time1 2 Equations 1 variable so solvable and Time1 comes out to be 30 mins.

Statement 2: Distance is given so if we use the main equation
Rate x Time = Distance (Work)
Rate1 x Time1 = 15
NOT SUFFICIENT

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Kudos [?]: 18 [0], given: 22

Intern
Status: Life begins at the End of your Comfort Zone
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Concentration: General Management, Technology
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14 Sep 2012, 12:06
Here we go, since the question is Data Sufficiency we do not need exact answer, just get the gist.

You know that Time = Distance/Speed, and from here we can find either value, yep?

Let the Speed be X, Distance D and Time Spent D/X - all the usual indicators

However, Today occurred some changes as follow:

TODAY: - Speed Today X/1.5 (1.5 times slower) and Time Spent 1.5D/X and the Distance remain the same, lets now move to options what we got:

1. From Statement 1 we get that 1.5D/X - D/X = 15/60 --->>>> a little bit manipulation gives us that D/X = 1/2, OR usual time (Before) it took Bill 1/2 hour or 30 minutes to drive to school, hence Sufficient.

2. The distance between home and school is irrelevant here, it can not help us that much, thus Insufficient.

Please, correct me if I went awry.

dczuchta wrote:
Driving 1.5 times slower, Bill was late for school today. What is the usual time it takes Bill to drive to school? (Assume that each day Bill takes the same route).

1) It took Bill 15 more minutes to drive to school today than usually
2) The distance between home and school is 15 miles

[Reveal] Spoiler: OA
A

Source: GMAT Club Tests - hardest GMAT questions

S1 tells us that on average Bill drives for 15 minutes less. Since he drove 1.5 times slower, the 15 minutes account for the difference. Therefore, it is possible to find the difference. (Can Someone Please Explain to Me Here In an Equation HOw we Can come up with that Answer if We Needed To. Thank you.

S2 does not tell us much; we don't really need to know the distance and by itself it is insufficeint.

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Last edited by Javoni on 14 Sep 2012, 12:17, edited 1 time in total.

Kudos [?]: 33 [0], given: 4

Math Expert
Joined: 02 Sep 2009
Posts: 41871

Kudos [?]: 128550 [1], given: 12180

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14 Sep 2012, 12:10
1
KUDOS
Expert's post
dczuchta wrote:
Driving 1.5 times slower, Bill was late for school today. What is the usual time it takes Bill to drive to school? (Assume that each day Bill takes the same route).

1) It took Bill 15 more minutes to drive to school today than usually
2) The distance between home and school is 15 miles

[Reveal] Spoiler: OA
A

Source: GMAT Club Tests - hardest GMAT questions

S1 tells us that on average Bill drives for 15 minutes less. Since he drove 1.5 times slower, the 15 minutes account for the difference. Therefore, it is possible to find the difference. (Can Someone Please Explain to Me Here In an Equation HOw we Can come up with that Answer if We Needed To. Thank you.

S2 does not tell us much; we don't really need to know the distance and by itself it is insufficeint.

BELOW IS REVISED VERSION OF THIS QUESTION:

On Tuesday it took Bill 1.5 times as long to drive from home to school as it took him the day before on Monday. How long did it take Bill to drive from home to school on Monday? (Assume that each day Bill takes the same route).

(1) On Tuesday it took Bill 15 minutes longer to drive from home to school than on Monday.
(2) The distance between home and school is 15 miles.

Suppose it took Bill $$t$$ minutes to drive from home to school on Monday, then on Tuesday, it would took him $$1.5t$$ minutes.

(1) On Tuesday it took Bill 15 minutes longer to drive from home to school than on Monday --> $$1.5t=t+15$$ --> $$t=30$$ minutes. Sufficient.

(2) The distance between home and school is 15 miles. Useless info. Not sufficient.

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Kudos [?]: 128550 [1], given: 12180

Math Expert
Joined: 02 Sep 2009
Posts: 41871

Kudos [?]: 128550 [0], given: 12180

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18 Jan 2013, 06:05
REVISED VERSION OF THIS QUESTION IS HERE: m04-70604-20.html#p1121614
_________________

Kudos [?]: 128550 [0], given: 12180

Manager
Joined: 13 Dec 2012
Posts: 194

Kudos [?]: 110 [1], given: 29

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18 Jan 2013, 06:36
1
KUDOS
dczuchta wrote:
Driving 1.5 times slower, Bill was late for school today. What is the usual time it takes Bill to drive to school? (Assume that each day Bill takes the same route).

1) It took Bill 15 more minutes to drive to school today than usually
2) The distance between home and school is 15 miles

[Reveal] Spoiler: OA
A

Source: GMAT Club Tests - hardest GMAT questions

S1 tells us that on average Bill drives for 15 minutes less. Since he drove 1.5 times slower, the 15 minutes account for the difference. Therefore, it is possible to find the difference. (Can Someone Please Explain to Me Here In an Equation HOw we Can come up with that Answer if We Needed To. Thank you.

S2 does not tell us much; we don't really need to know the distance and by itself it is insufficeint.

REVISED VERSION OF THIS QUESTION IS HERE: m04-70604-20.html#p1121614

When I saw this question today, I knew there was something wrong with it. How can you drive 1.5 times slower? That is 150% slower and more like a negative movement. The revised version makes more sense.
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Kudos [?]: 110 [1], given: 29

Manager
Joined: 05 Sep 2012
Posts: 78

Kudos [?]: 16 [0], given: 17

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18 Jan 2013, 09:12
Bunuel wrote:
REVISED VERSION OF THIS QUESTION IS HERE: m04-70604-20.html#p1121614

Yep the revised question makes complete sense. Thanks Bunuel.

Kudos [?]: 16 [0], given: 17

Re: M04 #1   [#permalink] 18 Jan 2013, 09:12

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# M04 #1

Moderator: Bunuel

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