Check GMAT Club Decision Tracker for the Latest School Decision Releases https://gmatclub.com/AppTrack

 It is currently 26 May 2017, 22:53

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# M04 #10

Author Message
Intern
Joined: 15 Jul 2013
Posts: 5
Followers: 0

Kudos [?]: 0 [0], given: 255

### Show Tags

05 Aug 2013, 15:32
eventually, is 0 even or it is neither even nor odd?
Math Expert
Joined: 02 Sep 2009
Posts: 38908
Followers: 7740

Kudos [?]: 106264 [1] , given: 11618

### Show Tags

11 Aug 2013, 02:14
1
KUDOS
Expert's post
gilda wrote:
eventually, is 0 even or it is neither even nor odd?

Zero is an even integer. (Zero is neither positive nor negative).

An even number is an integer that is "evenly divisible" by 2, i.e., divisible by 2 without a remainder and as zero is evenly divisible by 2 then it must be even (in fact zero is divisible by every integer except zero itself).

Hope it's clear.
_________________
Intern
Joined: 24 Jan 2013
Posts: 42
Followers: 1

Kudos [?]: 13 [0], given: 18

### Show Tags

12 Nov 2013, 09:41
Completely forgot that0!=1
Intern
Joined: 08 May 2014
Posts: 1
Followers: 0

Kudos [?]: 0 [0], given: 1

### Show Tags

15 May 2014, 07:58
Check out factorial explanation for those who are confused. This is an explanation from someone else that I liked and makes sense.

You cannot reason that x^0 = 1 by thinking of the meaning of powers as
"repeated multiplications" because you cannot multiply x zero times.
Similarly, you cannot reason out 0! just in terms of the meaning of
factorial because you cannot multiply all the numbers from zero down
to 1 to get 1.

Mathematicians *define* x^0 = 1 in order to make the laws of exponents
work even when the exponents can no longer be thought of as repeated
multiplication. For example, (x^3)(x^5) = x^8 because you can add
exponents. In the same way (x^0)(x^2) should be equal to x^2 by
adding exponents. But that means that x^0 must be 1 because when you
multiply x^2 by it, the result is still x^2. Only x^0 = 1 makes sense
here.

In the same way, when thinking about combinations we can derive a
formula for "the number of ways of choosing k things from a collection
of n things." The formula to count out such problems is n!/k!(n-k)!.
For example, the number of handshakes that occur when everybody in a
group of 5 people shakes hands can be computed using n = 5 (five
people) and k = 2 (2 people per handshake) in this formula. (So the
answer is 5!/(2! 3!) = 10).

Now suppose that there are 2 people and "everybody shakes hands with
everybody else." Obviously there is only one handshake. But what
happens if we put n = 2 (2 people) and k = 2 (2 people per handshake)
in the formula? We get 2! / (2! 0!). This is 2/(2 x), where x is the
value of 0!. The fraction reduces to 1/x, which must equal 1 since
there is only 1 handshake. The only value of 0! that makes sense here
is 0! = 1.

And so we define 0! = 1.
Manager
Joined: 20 Oct 2013
Posts: 66
Followers: 0

Kudos [?]: 3 [0], given: 27

### Show Tags

22 May 2014, 08:06
Statment 1: 0! or 1! insuff
statement 2: 0,2,4,6,8..., insuff

st1 & st2: x= even & x! =1....therefore x=0...
sufficient

C
_________________

Hope to clear it this time!!
GMAT 1: 540
Preparing again

Re: M04 #10   [#permalink] 22 May 2014, 08:06

Go to page   Previous    1   2   [ 25 posts ]

Similar topics Replies Last post
Similar
Topics:
3 m04 #24 24 15 Dec 2012, 10:25
7 M04 #1 26 18 Jan 2013, 09:12
32 M04 # 32 15 12 Oct 2012, 05:47
3 m04 Q23 12 07 Nov 2013, 06:53
23 M04 #12 93 28 Jul 2013, 22:11
Display posts from previous: Sort by

# M04 #10

Moderator: Bunuel

 Powered by phpBB © phpBB Group and phpBB SEO Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.