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Re: Sets Language [#permalink]
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05 Sep 2008, 07:58
Nerdboy wrote: I got A as well. Why is it incorrect? The answer is correct. (A) I mentioned earlier that, I made a silly mistake and lost my ability to think further at 1 am and posted the message
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Re: Sets Language [#permalink]
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05 Sep 2008, 21:36
leonidas wrote: 6 students in a group study different languages as specified: Russian: 4 Ukrainian: 3 Hebrew: 2 Each student studies at least 1 language. It is also known that exactly 3 students learn exactly 2 languages. How many students are studying all languages? a) 0 b) 1 c) 2 d) 3 e) 4 Even i got A Good question !!
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Re: Sets Language [#permalink]
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06 Sep 2008, 05:20
A for me too!!!
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m04  languages [#permalink]
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10 Sep 2008, 18:44
6 students in a group study different languages as specified:
* Russian: 4 * Ukrainian: 3 * Hebrew: 2
Each student studies at least 1 language. It is also known that exactly 3 students learn exactly 2 languages. How many students are studying all languages?
* 0 * 1 * 2 * 3 * 4



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Re: m04  languages [#permalink]
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10 Sep 2008, 20:02
sarzan wrote: 6 students in a group study different languages as specified:
* Russian: 4 * Ukrainian: 3 * Hebrew: 2
Each student studies at least 1 language. It is also known that exactly 3 students learn exactly 2 languages. How many students are studying all languages?
* 0 * 1 * 2 * 3 * 4 http://gmatclub.com/forum/7t69804



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6 students in a group study different languages as specified: * Russian: 4 * Ukrainian: 3 * Hebrew: 2 Each student studies at least 1 language. If it is also known that exactly 3 students study exactly 2 languages, how many students are studying all three languages? (A) 0 (B) 1 (C) 2 (D) 3 (E) 4 Source: GMAT Club Tests  hardest GMAT questions Can somebody explain with Venn diagram if possible?



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Re: m04 q19 [#permalink]
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27 Jan 2009, 11:14
n(RuUuH)= n(R)+n(U)+n(H)n(RnU)n(UnH)n(HnR)+n(RnUnH)
6 = 4 + 3 + 2  [3] + n(RnUnH) 6 = 6 + n(RnUnH) 0 = n(RnUnH)



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Re: m04 q19 [#permalink]
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28 Jan 2009, 06:21
Thanks, a lot! I got it now.



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6 students in a group study different languages [#permalink]
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30 Aug 2010, 11:11
6 students in a group study different languages as specified:
Russian: 4 Ukrainian: 3 Hebrew: 2
Each student studies at least 1 language. If it is also known that exactly 3 students study exactly 2 languages, how many students are studying all three languages?
0 1 2 3 4
How can we derive the answer with the below formula?
Total = n(A) + n(B) + n(C) – 2(Exactly 2) – 2 (A n B n C) + Neither.



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Re: 6 students in a group study different languages [#permalink]
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30 Aug 2010, 11:28
I normally use Venn diagram, however isn't the formula is Total = n(A) + n(B) + n(C) – (Exactly 2) – 2 (A n B n C) + Neither ? That gives the answer "0".



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Re: m04 q19 [#permalink]
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11 Oct 2010, 07:08
The anwer is 0 . its A



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Re: m04 q19 [#permalink]
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11 Oct 2010, 11:16
For a related question and explanation check out: overlappingsets99114.html



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Re: m04 q19 [#permalink]
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11 Oct 2010, 12:48
Well i did it this way...
6 students and 9 places up for grabs ( as R=4,U=3,H=2)... Now exactly 3 students study exactl;y 2 subjects..tht means 3x2=6 places out of the total 9.... 3 places remain...and 3 students remain. Since every student studies atleast one language, and only 3 places remain..therefore no single student studies all 3 languages..
Answer: 0
R J



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Re: m04 q19 [#permalink]
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11 Oct 2010, 22:29
A fresh outta my set questions yesterday :D
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Re: m04 q19 [#permalink]
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14 Oct 2010, 19:53
like in mgmat book they have solved some questions by table method while others through Venn diagram method.When i look at an overlapping set question,i get confused as which one of the two methods to apply.Any inputs



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overlapping sets [#permalink]
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03 Jan 2011, 17:19
6 students in a group study different languages as specified:
Russian: 4 Ukrainian: 3 Hebrew: 2 Each student studies at least 1 language. If it is also known that exactly 3 students study exactly 2 languages, how many students are studying all three languages?
a 0 b 1 c 2 d 3 e 4



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Re: overlapping sets [#permalink]
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05 Jan 2011, 01:36
yep it is 0. Students who are taking 2 languages: 1 stud(Rus, Ukr) 1 stud(Rus, Heb) 1 stud(Ukr, Rus)=>in this case 2 rus+1 urk+1 heb=4, if one takes 3 languages, then one student will be left with 0. , so no one can take three languages. In other cases, still no one can take three languages.



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Re: overlapping sets [#permalink]
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05 Jan 2011, 02:29
6= 9  3(two languages)+x(all three)+0(who dont study any of the languages) 6=93+X+0 X=0Ans.A



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Re: 6 students in a group study different languages [#permalink]
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25 Jun 2011, 10:42
A!
Used the formula
T = G1 + G2 + G3  (those in 2 of the groups)  2*(those in all 3 groups)
Nice question!



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Re: 6 students in a group study different languages [#permalink]
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25 Jun 2011, 15:04
\(A U B U C=A+B+CA intersection BB intersection C C intersection A + A intersection B intersection C\)
=>6 = 4+3+23+all three => all three = 0
Answer is A.




Re: 6 students in a group study different languages
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