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M05-10

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Director
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Joined: 22 Nov 2018
Posts: 534
Location: India
GMAT 1: 640 Q45 V35
GMAT 2: 660 Q48 V33
M05-10  [#permalink]

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New post 15 Jun 2019, 23:23
pm0103 wrote:
Bunuel wrote:
There are 6 cards numbered from 1 to 6. They are placed into a box, and then one is drawn and put back. Then another card is drawn and put back. If the sum of the two cards was 8, what is the probability that one of the cards drawn was a 5?

A. 1
B. \(\frac{2}{3}\)
C. \(\frac{1}{2}\)
D. \(\frac{2}{5}\)
E. \(\frac{1}{3}\)


Hello Bunuel,
Could you please point out mistake in my interpretation:
(Probability of drawing a 5 and a 3 ) * 2 ( for reverse of it)
1/6 * 1/6 * 2 = 1/18


pm0103 You are ignoring the fact that the stem says sum of the numbers picked is 8. You are trying to arrive at the prob of picking 3 and 5 initially from 1-6 cards with repetition, where as the question says already the cards are picked and you have a sum of 8(4,4/6,2/2,6/3,5/5,3) and requires what is the prob of one of the cards being a 5. Which is 2/5.

Hope this helps!

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GMAT Club Bot
M05-10   [#permalink] 15 Jun 2019, 23:23

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