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# m05#36

Author Message
Director
Joined: 03 Jun 2009
Posts: 782

Kudos [?]: 902 [0], given: 56

Location: New Delhi
WE 1: 5.5 yrs in IT

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31 Jul 2009, 10:28
if a, b, and c are positive distinct integers, is $$(a/b)/c$$ an integer ?

1. c = 2
2. a = b + c
_________________

Kudos [?]: 902 [0], given: 56

Intern
Joined: 08 May 2009
Posts: 21

Kudos [?]: 1 [0], given: 0

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31 Jul 2009, 12:16
Will try to apply my brains.

E.

(a/b)/c = a/bc

1. S1 is insuff. Does not tell us anything about a,b

2. S2 is insuff.
Plugging values
a = b+ c
a = 4, b = 2, c = 2 => a/bc = 1 = Integer = True
a = 5, b = 2, c = 3 - Not True

3. S1 and S2
c = 2, but b can be anything, hence a can be anything. Not suff.

Kudos [?]: 1 [0], given: 0

Director
Joined: 03 Jun 2009
Posts: 782

Kudos [?]: 902 [0], given: 56

Location: New Delhi
WE 1: 5.5 yrs in IT

### Show Tags

31 Jul 2009, 12:41
proych wrote:
Will try to apply my brains.

E.

(a/b)/c = a/bc

1. S1 is insuff. Does not tell us anything about a,b

2. S2 is insuff.
Plugging values
a = b+ c
a = 4, b = 2, c = 2 => a/bc = 1 = Integer = True
a = 5, b = 2, c = 3 - Not True

3. S1 and S2
c = 2, but b can be anything, hence a can be anything. Not suff.

Thanks a lot buddy. From your post I have got the explanation. Btw, OA is B.
The only mistake you did in you calculation is missing the point "positive distinct integers". So while plugging the values, the combination a = 4, b = 2, c = 2 cannot be true
_________________

Kudos [?]: 902 [0], given: 56

Re: m05#36   [#permalink] 31 Jul 2009, 12:41
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# m05#36

Moderator: Bunuel

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