One thought that helped me for statement (2), was figuring out extreme cases.
If B covers almost the whole distance in 20 minutes (C has to be super fast then), B will stand pretty much in front of the door of the studio and will meet C definitely closer to the studio.
But if B covers an infinitesimal small fraction of the distance (C has to be only a little faster than B), they will meet pretty much at exactly halfway between the trailer and the studio.
So technically, they will always meet at a point closer to the studio than to the trailer. But this difference between the point halfway between the studios and the point where they meet, approaches 0 as the total distance between trailer and studio approaches infinity.

S1 talks only about C's speed. Ignore!

S2 states that B and C take the same time to reach their destination. This would mean if they meet somewhere in between then the time taken by them to reach their destination after the meeting point will be equal. So, in the D=ST equation, the time is constant so the speed is proportional to the distance. Since B moves with a relatively slower speed he will cover a smaller distance, which means B is closer to his destination (studio).

sir, Bunuel

I think (1) is suff; Can please you point out my mistake?

here is my reasoning:
Buster leaves the trailer at noon and 20 minutes later, Charlie leaves

So if Charlie took 55 mins then we know Buster took 75 mins.

Now if distance between them is same then; speed * time are constant for both.

comparing both their equations we can ratio of their speed. Once we know the ratio of speed we can determine who will reach any destination quicker.

thnks
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The red part is not correct. How do you know that Buster would need 75 minutes to reach the studio? Are we told that they reach destination at the same time?
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I think this is a high-quality question and I agree with explanation.

B takes 20 mins more than C to cover the same distance which means speed of c > speed of b.
Also they reach their destinations at the same time which means, after crossing each other they take the same amount of time to reach their destinations. So let's imagine the point at which they cross each other And turn B around. Then conduct a race.. C would beat B as C has a higher speed. So basically b can reach the other end while racing with c but can't reach its origin while racing with C in the same amount of time. Only possible if distance to the other end is smaller.

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Good Question:

Can also be done as . B takes 20 minutes after that C starts. In 20 minutes B has travelled B/3. Left is 2/3 of B. Now. As, if 1/3 B of B covered in 20 minutes, total B will be covered in 60 minutes. So total distance is 60. 20 is done. Now, C takes the same time to cover the distance as B does. Thus 20B + 40 B = 40 C. Thus B:C = 2:3. So distance travelled by B after 20 minutes to meet at the meeting point will be 2/5(40) = 16. So total distance travelled by B = 20 + 16 = 36. Total distance travelled by C = 40-16 = 24.