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# M10:Q5 - DS

Author Message
Intern
Status: Active
Joined: 30 Jun 2012
Posts: 37

Kudos [?]: 94 [0], given: 36

Location: India

### Show Tags

25 Dec 2012, 06:42
Bunuel,

Please point out where I am going wrong.

Area of rectangle/sqaure (assumption: TV is either rectangle or square) = $$\frac{d^2}{2}$$ where d = diagonal.

So, doesn't question itself suffice, in this case?
_________________

Thanks and Regards!

P.S. +Kudos Please! in case you like my post.

Kudos [?]: 94 [0], given: 36

Intern
Status: Active
Joined: 30 Jun 2012
Posts: 37

Kudos [?]: 94 [0], given: 36

Location: India

### Show Tags

25 Dec 2012, 06:46
Bunuel,

Please point out where I am going wrong. May be I am getting confused here..

Area of rectangle/sqaure (assumption: TV is either rectangle or square) = $$\frac{d^2}{2}$$ where d = diagonal.

So, doesn't question itself suffice, in this case?
_________________

Thanks and Regards!

P.S. +Kudos Please! in case you like my post.

Kudos [?]: 94 [0], given: 36

Intern
Joined: 06 Jun 2012
Posts: 7

Kudos [?]: [0], given: 1

GMAT Date: 10-16-2013
WE: Project Management (Health Care)

### Show Tags

07 Jan 2013, 02:45
"In two similar triangles (or rectangles), the ratio of their areas is the square of the ratio of their sides." - Can you explain how can this be derived with simple proof?

Kudos [?]: [0], given: 1

Math Expert
Joined: 02 Sep 2009
Posts: 42544

Kudos [?]: 135260 [0], given: 12679

### Show Tags

07 Jan 2013, 04:55
Bunuel,

Please point out where I am going wrong.

Area of rectangle/sqaure (assumption: TV is either rectangle or square) = $$\frac{d^2}{2}$$t where d = diagonal.

So, doesn't question itself suffice, in this case?

Area of rectangle does not equal to $$\frac{d^2}{2}$$.
_________________

Kudos [?]: 135260 [0], given: 12679

Re: M10:Q5 - DS   [#permalink] 07 Jan 2013, 04:55

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# M10:Q5 - DS

Moderator: Bunuel

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