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M10:Q5 - DS

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Intern
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Re: M10:Q5 - DS [#permalink]

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New post 25 Dec 2012, 06:42
Bunuel,

Please point out where I am going wrong.

Area of rectangle/sqaure (assumption: TV is either rectangle or square) = \(\frac{d^2}{2}\) where d = diagonal.

So, doesn't question itself suffice, in this case?
_________________

Thanks and Regards!

P.S. +Kudos Please! in case you like my post. :)

Kudos [?]: 89 [0], given: 36

Intern
Intern
User avatar
Status: Active
Joined: 30 Jun 2012
Posts: 37

Kudos [?]: 89 [0], given: 36

Location: India
Re: M10:Q5 - DS [#permalink]

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New post 25 Dec 2012, 06:46
Bunuel,

Please point out where I am going wrong. May be I am getting confused here..

Area of rectangle/sqaure (assumption: TV is either rectangle or square) = \(\frac{d^2}{2}\) where d = diagonal.

So, doesn't question itself suffice, in this case?
_________________

Thanks and Regards!

P.S. +Kudos Please! in case you like my post. :)

Kudos [?]: 89 [0], given: 36

Intern
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Joined: 06 Jun 2012
Posts: 7

Kudos [?]: [0], given: 1

Concentration: Operations, International Business
GMAT Date: 10-16-2013
WE: Project Management (Health Care)
Re: M10:Q5 - DS [#permalink]

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New post 07 Jan 2013, 02:45
"In two similar triangles (or rectangles), the ratio of their areas is the square of the ratio of their sides." - Can you explain how can this be derived with simple proof?

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Re: M10:Q5 - DS [#permalink]

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New post 07 Jan 2013, 04:55
goutamread wrote:
Bunuel,

Please point out where I am going wrong.

Area of rectangle/sqaure (assumption: TV is either rectangle or square) = \(\frac{d^2}{2}\)t where d = diagonal.

So, doesn't question itself suffice, in this case?


Area of rectangle does not equal to \(\frac{d^2}{2}\).
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Kudos [?]: 124029 [0], given: 12070

Re: M10:Q5 - DS   [#permalink] 07 Jan 2013, 04:55

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