It is currently 17 Nov 2017, 20:15

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# M11 #32

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
Manager
Joined: 25 May 2009
Posts: 142

Kudos [?]: 152 [0], given: 2

Concentration: Finance
GMAT Date: 12-16-2011
M11 #32 [#permalink]

### Show Tags

01 Jul 2009, 20:34
If a square is inscribed in a circle of radius 4, what is the area of the square?

(C) 2008 GMAT Club - m11#32

* 8
* 16
* 32
* 48
* 64

[Reveal] Spoiler:
The diameter of the circle is the diagonal of the square. The side of the square is $$2*\sqrt{8}$$ , therefore the area of the square is 32. The correct answer is C.

How do you get 2*sqrt(8) for each side? I was getting 4 which is x^2+x^2=8^2, so x=4. Please explain how do solve for the sides using Pythagorean theorem.

Kudos [?]: 152 [0], given: 2

Manager
Joined: 30 May 2009
Posts: 214

Kudos [?]: 135 [0], given: 0

Re: M11 #32 [#permalink]

### Show Tags

01 Jul 2009, 20:57
If a square is inscribed in a circle of radius 4, what is the area of the square?

* 8
* 16
* 32
* 48
* 64

The diameter is 8 = Diagonal of the square.
But diagonal of a square with side a $$= a\sqrt{2}$$
Hence if $$8 = a\sqrt{2}$$, then we can see that side of the sqaure $$= a = \frac{8}{\sqrt{2}}$$
Therefore, area $$= a^2 = \left(\frac{8}{\sqrt{2}}\right)^2 = 32$$

Kudos [?]: 135 [0], given: 0

Manager
Joined: 25 May 2009
Posts: 142

Kudos [?]: 152 [0], given: 2

Concentration: Finance
GMAT Date: 12-16-2011
Re: M11 #32 [#permalink]

### Show Tags

02 Jul 2009, 05:09
Still not understanding. Any help?
I think its a notation problem above. what does the /\ mean?

Kudos [?]: 152 [0], given: 2

Manager
Joined: 25 May 2009
Posts: 142

Kudos [?]: 152 [0], given: 2

Concentration: Finance
GMAT Date: 12-16-2011
Re: M11 #32 [#permalink]

### Show Tags

07 Jul 2009, 05:00
sdrandom1 wrote:
If a square is inscribed in a circle of radius 4, what is the area of the square?

The diameter is 8 = Diagonal of the square.
But diagonal of a square with side $$a = a\sqrt{2}$$
Hence if $$8 = a\sqrt{2}$$, then we can see that side of the sqaure = $$a = 8/\sqrt{2}$$
Therefore, area = $$a^2 = (8/\sqrt{2})^2 = 32$$

Got it now, the math formulas weren't working, its easier to understand now above. Thanks sdrandom1.

Kudos [?]: 152 [0], given: 2

CIO
Joined: 02 Oct 2007
Posts: 1216

Kudos [?]: 986 [0], given: 334

Re: M11 #32 [#permalink]

### Show Tags

07 Jul 2009, 06:25
I've edited the post above so that math expressions work.

In order for the math expressions to work fine, one needs to enclose the whole expression in the "m" tag, which is next to the "fraction" tag in the edit page. This won't work (without the "m" tag):

Code:
[square_root]x^2 -2x +1[/square_root] = [square_root](x-1)^2[/square_root] = |x-1|

\sqrt{x^2 -2x +1} = \sqrt{(x-1)^2} = |x-1|

This will work (just add the "m" tag):

Code:
[m][square_root]x^2 -2x +1[/square_root] = [square_root](x-1)^2[/square_root] = |x-1|[/m]

$$\sqrt{x^2 -2x +1} = \sqrt{(x-1)^2} = |x-1|$$

Remember to use only one "m" tag for the whole expression, no need to enclose every single unit in it.

Hope this helps.
_________________

Welcome to GMAT Club!

Want to solve GMAT questions on the go? GMAT Club iPhone app will help.
Please read this before posting in GMAT Club Tests forum
Result correlation between real GMAT and GMAT Club Tests
Are GMAT Club Test sets ordered in any way?

Take 15 free tests with questions from GMAT Club, Knewton, Manhattan GMAT, and Veritas.

GMAT Club Premium Membership - big benefits and savings

Kudos [?]: 986 [0], given: 334

Re: M11 #32   [#permalink] 07 Jul 2009, 06:25
Display posts from previous: Sort by

# M11 #32

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics

Moderator: Bunuel

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.