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M13-23

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Manager
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Joined: 17 May 2017
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Re: M13-23 [#permalink]

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New post 11 Sep 2017, 23:11
still confused if we take x= 5 then a can be both positive and negative so how is the first statement sufficient?
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Re: M13-23 [#permalink]

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New post 17 Sep 2017, 04:56
Bunuel : Can you help me with a simple question:

Why haven't you used discriminant method to solve Option B as well. If you solve it using D method, you will get A>0, what am I missing here please?
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Re M13-23 [#permalink]

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New post 22 Sep 2017, 23:17
I think this is a high-quality question and I agree with explanation. Hi Bunuel,
Is the following approach for statement-1 wrong?
x^2-2x+a is positive for all values of x,
Hence it should hold its ground even when x=0.
So, when x=0,
x^2-2x+a is reduced to a
Hence a has to be greater than 0.
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Re: M13-23 [#permalink]

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New post 13 Jan 2018, 04:44
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Hi Bunnel ,

I too have same doubt that why imaginary roots discriminant method is not used in S2 if used you will get a>0 but also actually it is not true as a=0 also satisfies the equation which is the reason for insufficiency.

So m main doubt is Can I know whether discriminant method is suffice(S1) or not (S2) for checking whether statements suffice or not
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Re: M13-23   [#permalink] 13 Jan 2018, 04:44

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