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1. \(a\) , \(b\) , and \(c\) are consecutive even integers 2. \(a*b\) is divisible by 12

Solution:

Statement (1) by itself is sufficient. One of any three consecutive even integers is divisible by 3. Because this integer is even, it is also divisible by 6. When multiplied by two more even integers, it renders a product that is divisible by 24.

Statement (2) by itself is insufficient. We need to know something about \(c\) .

As per me, 0 is an even number. So, as per S1, if a, b and c are consecutive integers, it can be even 0,2,4. Then in that case, number won't be divisible by 24.

1. \(a\) , \(b\) , and \(c\) are consecutive even integers 2. \(a*b\) is divisible by 12

Solution:

Statement (1) by itself is sufficient. One of any three consecutive even integers is divisible by 3. Because this integer is even, it is also divisible by 6. When multiplied by two more even integers, it renders a product that is divisible by 24.

Statement (2) by itself is insufficient. We need to know something about \(c\) .

As per me, 0 is an even number. So, as per S1, if a, b and c are consecutive integers, it can be even 0,2,4. Then in that case, number won't be divisible by 24.

Hence, the answer should be 'c'.

Guys please confirm !!

0*2*4 = 0 0/24 = 0 Answer results in an integer which means 0 is divisible by 24