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M14 Q3 - Why isn't 0 "a term"

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M14 Q3 - Why isn't 0 "a term" [#permalink]

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New post 15 Sep 2009, 00:48
A sequence is defined as follows:

An = n/n+1

How many of the first 100 terms of this sequence are less than 0.891?

A-7
B-8
C-9
D-10
E-12

I got this question wrong by considering and counting 0 as a term, yielding 0% as one of the terms below 0.891. I'm sure this is obvious to most, but how is one to know that 0 isnt a term when interpreting the question?

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Re: M14 Q3 - Why isn't 0 "a term" [#permalink]

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New post 13 Oct 2009, 05:59
dpgxxx wrote:
A sequence is defined as follows:

An = n/n+1

How many of the first 100 terms of this sequence are less than 0.891?

A-7
B-8
C-9
D-10
E-12

I got this question wrong by considering and counting 0 as a term, yielding 0% as one of the terms below 0.891. I'm sure this is obvious to most, but how is one to know that 0 isnt a term when interpreting the question?



Can someone help here as to why "0" cannot be considered :?:
The question doesnt say anything about "n", to be considered as natural or whole number or integers.. :?

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Re: M14 Q3 - Why isn't 0 "a term" [#permalink]

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New post 13 Oct 2009, 07:21
We should probably state that the first element of the sequence is \(\frac{1}{2}\). However, I thought it goes without saying that the first element is found by plugging "1", the second one by plugging "2" and so on. There's no zero element of a sequence, it starts with the first element.
Anyone else thinks we should specify the first element of the sequence?
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Re: M14 Q3 - Why isn't 0 "a term" [#permalink]

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New post 13 Oct 2009, 07:38
u r right .. we always start a series with 1.. as also seen while calculating sum of first n nos etc
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Re: M14 Q3 - Why isn't 0 "a term" [#permalink]

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New post 13 Oct 2009, 10:26
chetan2u wrote:
u r right .. we always start a series with 1.. as also seen while calculating sum of first n nos etc


do we not consider the series here as sum of 1st n NATURAL numbers? wherein the first number is 1 :? whereas the above series doesnt mention anything specific

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Re: M14 Q3 - Why isn't 0 "a term" [#permalink]

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New post 13 Oct 2009, 10:32
dzyubam wrote:
We should probably state that the first element of the sequence is \(\frac{1}{2}\). However, I thought it goes without saying that the first element is found by plugging "1", the second one by plugging "2" and so on. There's no zero element of a sequence, it starts with the first element.
Anyone else thinks we should specify the first element of the sequence?


really sorry but still not able to get it :( :x ...as per my understanding until and unless it is not mentioned specifically we can consider any number which fits the equation....that goes without saying that we can consider -ve number,fraction as well.

Kindly explain what is meant by zero element? is it meaning A0 is the zero element and cannot be considered?

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Re: M14 Q3 - Why isn't 0 "a term" [#permalink]

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New post 13 Oct 2009, 11:21
looks like the question is not fully correct, it misses one of the premises to specify a range for n.

first element will be the one where n has the least value as specified by the n's range of allowable values; for eg., if it was specified that n is an integer always greater than -5 then first element is -4/-3 = 4/3 (where n= -4)
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Re: M14 Q3 - Why isn't 0 "a term" [#permalink]

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New post 13 Oct 2009, 11:28
OK. So would adding the following to the question stem suffice:

"\(n\) is a positive integer"

?

If so, I'll add the statement to the stem. Thank you guys for your feedback! :)
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Re: M14 Q3 - Why isn't 0 "a term" [#permalink]

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New post 13 Oct 2009, 11:36
dzyubam wrote:
OK. So would adding the following to the question stem suffice:

"\(n\) is a positive integer"

?

If so, I'll add the statement to the stem. Thank you guys for your feedback! :)


that will definitely help in clearing my confusion :-D

thanks dzyubam

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Re: M14 Q3 - Why isn't 0 "a term" [#permalink]

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New post 15 Oct 2009, 02:00
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The question has been changed to this:

A sequence is defined as follows:
\(A_n = \frac{n}{n + 1}\)

If \(n\) is a positive integer, then how many of the first 100 terms of this sequence are less than 0.891?

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Re: M14 Q3 - Why isn't 0 "a term" [#permalink]

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New post 29 Jan 2010, 07:19
It should be changed in the stem of the hardest questions as well
ie: Algebra I - Q3

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Re: M14 Q3 - Why isn't 0 "a term"   [#permalink] 29 Jan 2010, 07:19
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