BankerBro wrote:
Bunuel VeritasKarishmaThis is high quality question indeed, but the explanation isn't clear.
Using the basics of Combinatorics, we have to arrange 15 boxes in 6 positions.
So, it can be written as 15P6, where P stands for Permutations.
The expression can be written as 15! / (15-6)! or 15! / 9!.
Now the resultant is to be divided by 5! * 5! * 5!, because we have 5 identical items for all three colours.
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What's wrong in this approach ?
This is not correct.
15P6 is "select 6 elements from 15 distinct elements and arrange the 6 selected"
Here, we do not have 15 distinct elements. 5 are white (identical), 5 red (identical) and 5 black (identical).
But note that each of the 6 block spaces on the floor are distinct.
For each spot, there are 3 ways (white, red or black) giving us 3*3*3*3*3*3 = 729 ways
But in 3 of these, all blocks are of the same colour (All 6 blocks are red or all are white or all are black). We need to remove these because we have only 5 of each block type.
Hence we get 726 total arrangements.
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