Last visit was: 25 Apr 2024, 13:09 It is currently 25 Apr 2024, 13:09

Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
SORT BY:
Kudos
Math Expert
Joined: 02 Sep 2009
Posts: 92915
Own Kudos [?]: 619009 [27]
Given Kudos: 81595
Send PM
Intern
Intern
Joined: 21 Jan 2017
Posts: 4
Own Kudos [?]: 1 [1]
Given Kudos: 78
Send PM
Math Expert
Joined: 02 Sep 2009
Posts: 92915
Own Kudos [?]: 619009 [1]
Given Kudos: 81595
Send PM
Manager
Manager
Joined: 22 Jun 2017
Posts: 239
Own Kudos [?]: 613 [0]
Given Kudos: 149
Location: Argentina
GMAT 1: 630 Q43 V34
GMAT 2: 710 Q50 V36 (Online)
Send PM
Re: M16-08 [#permalink]
I think this is a high-quality question and I agree with explanation.
Intern
Intern
Joined: 15 Jul 2016
Posts: 46
Own Kudos [?]: 22 [0]
Given Kudos: 60
Location: India
Concentration: Finance, Strategy
GMAT 1: 750 Q49 V41
GPA: 4
WE:Consulting (Consulting)
Send PM
Re: M16-08 [#permalink]
I think this is a high-quality question and I agree with explanation.
Math Expert
Joined: 02 Sep 2009
Posts: 92915
Own Kudos [?]: 619009 [0]
Given Kudos: 81595
Send PM
Re: M16-08 [#permalink]
Expert Reply
I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
Intern
Intern
Joined: 30 Dec 2021
Posts: 1
Own Kudos [?]: 0 [0]
Given Kudos: 5
Send PM
Re: M16-08 [#permalink]
Why do we assume that first half of the distance is 150 miles. As nowhere it is mentioned that the first 2 hours of the trip has covered half of the distance. Please can I get a more detailed explanation for this.
Math Expert
Joined: 02 Sep 2009
Posts: 92915
Own Kudos [?]: 619009 [0]
Given Kudos: 81595
Send PM
Re: M16-08 [#permalink]
Expert Reply
Ashu101 wrote:
Why do we assume that first half of the distance is 150 miles. As nowhere it is mentioned that the first 2 hours of the trip has covered half of the distance. Please can I get a more detailed explanation for this.


Read carefully:

(1)+(2) From (1), we know that in the first 2 hours, the bus covered a distance of 150 miles. From (2), we know that it took the bus 2 hours to cover the first half of the distance. Consequently, the entire journey was 300 miles long. As it took 6 hours to cover this distance, the average speed for the entire trip was 300/6 = 50 miles per hour. Sufficient.

first 2 hours --> 150 miles
2 hours --> half of the distance

Hence, 150 miles = half of the distance.
Manager
Manager
Joined: 07 Mar 2020
Posts: 119
Own Kudos [?]: 67 [0]
Given Kudos: 52
GMAT 1: 680 Q49 V34
Send PM
Re: M16-08 [#permalink]
Ashu101 wrote:
Why do we assume that first half of the distance is 150 miles. As nowhere it is mentioned that the first 2 hours of the trip has covered half of the distance. Please can I get a more detailed explanation for this.


We need \(Avg(speed)=\frac{total distance}{total time taken}\)
Statement 1: in first 2 hrs, bus covered 150miles, here speed = \(\frac{150}{2}=75\)miles/hr. We know nothing about distance in next 4 hrs. Hence Insufficient.

Statement 2: Speed in first half is 2 times speed in second half . Let total distance be d. We know speed is inversely proportional to time if distance is constant [from \(speed=\frac{distance}{time}\)]. Here distance is same. So we can say 2t1=t2. We know \(t1+t2=6\). Hence t1=2, and t2=4.
But again no info on distance. Hence insufficient.

Both : We know t1=2hrs, and we know first half takes 2 hrs (inferred from statement 2), so obviously second will also be 150 miles.
Using \(Avg(speed)=\frac{total distance}{total time taken}\); \(speed=(150+150)/6\)=50miles/hrs.

C is the answer
Intern
Intern
Joined: 03 May 2023
Posts: 22
Own Kudos [?]: 2 [0]
Given Kudos: 0
Location: Indonesia
Schools: Sloan '26
GRE 1: Q166 V163
GPA: 3.01
Send PM
M16-08 [#permalink]
Hi Bunuel

I still can't get the logic as to the logic of getting the amount of total distance, there seems to be a jump from 150 from statement (1) to the 300 in the (1)+(2)

Analyzing your statements
- "From (1), we know that in the first 2 hours, the bus covered a distance of 150 miles"
sure, I have no problem

- "From (2), we know that it took the bus 2 hours to cover the first half of the distance"
There is nowhere in the text that indicates the two hours from the first statement is the actual distance, statement (1) only says that it takes 2 hours and a 150 miles, nothing about the 150 miles being half of the distance. Thus, since we don't know the remaining distance, we cannot get the average.

It would be different if statement (2) said that it took 2 hrs to reach half of the distance eg "The average speed of the bus for the first half of the distance was twice its average speed for the second half of the distance and the bus took 2 hrs to cover half the distance"

or statement (1) said that the 150 is half of the distance eg "In the first 2 hours, the bus covered a distance of 150 miles which is half of the distance required"
There is a disconnect between the two

please advise


Bunuel wrote:
Ashu101 wrote:
Why do we assume that first half of the distance is 150 miles. As nowhere it is mentioned that the first 2 hours of the trip has covered half of the distance. Please can I get a more detailed explanation for this.


Read carefully:

(1)+(2) From (1), we know that in the first 2 hours, the bus covered a distance of 150 miles. From (2), we know that it took the bus 2 hours to cover the first half of the distance. Consequently, the entire journey was 300 miles long. As it took 6 hours to cover this distance, the average speed for the entire trip was 300/6 = 50 miles per hour. Sufficient.

first 2 hours --> 150 miles
2 hours --> half of the distance

Hence, 150 miles = half of the distance.
Math Expert
Joined: 02 Sep 2009
Posts: 92915
Own Kudos [?]: 619009 [0]
Given Kudos: 81595
Send PM
Re: M16-08 [#permalink]
Expert Reply
r_putra_rp wrote:
Hi Bunuel

I still can't get the logic as to the logic of getting the amount of total distance, there seems to be a jump from 150 from statement (1) to the 300 in the (1)+(2)

Analyzing your statements
- "From (1), we know that in the first 2 hours, the bus covered a distance of 150 miles"
sure, I have no problem

- "From (2), we know that it took the bus 2 hours to cover the first half of the distance"
There is nowhere in the text that indicates the two hours from the first statement is the actual distance, statement (1) only says that it takes 2 hours and a 150 miles, nothing about the 150 miles being half of the distance. Thus, since we don't know the remaining distance, we cannot get the average.

It would be different if statement (2) said that it took 2 hrs to reach half of the distance eg "The average speed of the bus for the first half of the distance was twice its average speed for the second half of the distance and the bus took 2 hrs to cover half the distance"

or statement (1) said that the 150 is half of the distance eg "In the first 2 hours, the bus covered a distance of 150 miles which is half of the distance required"
There is a disconnect between the two

please advise


Bunuel wrote:
Ashu101 wrote:
Why do we assume that first half of the distance is 150 miles. As nowhere it is mentioned that the first 2 hours of the trip has covered half of the distance. Please can I get a more detailed explanation for this.


Read carefully:

(1)+(2) From (1), we know that in the first 2 hours, the bus covered a distance of 150 miles. From (2), we know that it took the bus 2 hours to cover the first half of the distance. Consequently, the entire journey was 300 miles long. As it took 6 hours to cover this distance, the average speed for the entire trip was 300/6 = 50 miles per hour. Sufficient.

first 2 hours --> 150 miles
2 hours --> half of the distance

Hence, 150 miles = half of the distance.



(1) says: In the FIRST 2 hours, the bus covered a distance of 150 miles.
(2) says: The bus took 2 hours to cover the FIRST HALF of the distance and 4 hours to cover the SECOND HALF of the distance.

(1)+(2) In the FIRST 2 hours, in which the bus covered the FIRST HALF of the distance, the bus covered a distance of 150 miles. Consequently, the entire journey was 300 miles long. As it took 6 hours to cover this distance, the average speed for the entire trip was 300/6 = 50 miles per hour. Sufficient.

Hope now it's clear.
Intern
Intern
Joined: 18 Sep 2022
Posts: 38
Own Kudos [?]: 17 [0]
Given Kudos: 442
Location: United Arab Emirates
GMAT 1: 660 Q48 V34
GMAT 2: 710 Q48 V40
Send PM
Re: M16-08 [#permalink]
What a beautiful question!
GMAT Club Bot
Re: M16-08 [#permalink]
Moderator:
Math Expert
92914 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne