martinjudge91 wrote:

Hello Bunuel,

correct me if I'am wrong about my explanation with satement II.

As we know that there has to be a right angle at point D or C of your chart we can determine the length of the legs by applying the Pythagoras' theorem, which defines the lenght of the hypotheneuse that is 5 in this example. Thus the only combination of the both legs is a 3-4-5 trinagle which yields an area smaller than 15. Thus, statement 2 is sufficient on its own.

this is great solution! thank you!